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SashulF [63]
3 years ago
12

Please help:(((( I attached the image of the question

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
6 0
90 feet of wire because 3 squared is 9 and 4 squared is 16 so 16+9=25 and the square root of 25 is 5 and 5*3=15 so that is 15 feet for one tree so 15*6=90
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Where should the lower quartile line be placed?
makvit [3.9K]
Between the median and the number before it and everything in front of it is the lower quartile
5 0
3 years ago
the perimeter of a rectangle is 40m. one of the lengths or the sides is 5m. find the lengths of the other 3 sides.​
Annette [7]

The perimeter of a rectangle is 40m and one side of it is 5m. What is the length of the other side using an equation?

Perimeter of the rectangle =2(l+ b)=40m

If one of its side b=5, then l = (40/2)-5

= 20–5

= 15 m Therefore

Length= 15 cm

Breadth =5 cm

4 0
3 years ago
Read 2 more answers
5<br> 2<br> A line passes through the point (-10, 8) and has a slope of
Nezavi [6.7K]

Answer:

you need more than one point to find the slope of a line?

Step-by-step explanation:

3 0
3 years ago
a plane travels at a speed of 180 mph in still air. flying with a tailwind, the plane is clocked over a distance of 700 miles. f
galben [10]
<h3>Answer: approximately 43.57337308309 mph</h3>

Round this value however you need to

===========================================================

Explanation:

w = speed of the wind

The plane travels at a speed of 180 mph in still air. With a tailwind, the plane speeds up (the wind is coming from the tail to push the plane forward more), so the plane is now traveling at a speed of 180+w miles per hour. It travels 700 miles

d = r*t

700 = (180+w)*t

t = 700/(180+w)

This is the time it takes when the wind speeds up the plane.

In contrast, the headwind slows the plane down because now the wind is going against the plane. Headwinds attack the head of the plane and push against the plane. With a headwind, the plane is now going 180-w miles per hour. It travels for 2 hours longer to do the return trip (of 700 miles), so,

d = r*t

700 = (180-w)*(t+2)

700 = 180t + 360 - w*t - 2w

700 = 180( 700/(180+w) ) + 360 - w*( 700/(180+w) ) - 2w

700 = 126000/(180+w) + 360 - 700w/(180+w) - 2w

700(180+w) = 126000 + 360(180+w) - 700w - 2w(180+w)

126000+700w = 126000+64800+360w-700w-360w-2w^2

126000+700w = -2w^2 - 700w + 190800

-2w^2 - 700w + 190800 = 126000+700w

-2w^2 - 700w + 190800 - 126000-700w = 0

-2w^2 - 1400w + 64800 = 0

Use a graphing calculator or the quadratic formula to find the approximate solutions are

w = -743.5733730831, w = 43.57337308309

Ignore the negative value as it makes no sense to have a negative wind speed.

The only practical answer is approximately 43.57337308309 mph

4 0
4 years ago
Pls help me with my work
Kruka [31]
The equation you are looking for is P(1 + r/n)^nt, which is 320,000(1+0.0575)^10 = 559,698
6 0
2 years ago
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