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nataly862011 [7]
3 years ago
8

Pls I beg someone to finish ALL of this :(. I’ve stayed up all night to do this but I couldn’t figure all of them out. Pls pls p

ls!!! ill mark you brainliest n I can give you a thank you such as 5 Stars in return. Please take your time and I hope you all have a amazing day!

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer:

9. 1:53

10. 4:17

11. 2:52

12. 3:35

This should be it have a great day buddy!

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KengaRu [80]

Answer: 21,400 mg

Step-by-step explanation: Multiply the mass value by 1000 .

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Click on the numbers to enter the answers in the boxes.​
djyliett [7]

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957 - 249 = 708

The number that goes above the 5 is 4

Number above the 7 is 17

Step-by-step explanation:

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3. A building stands on level ground. The measure of the angle of elevation of the top of the building, taken at a
Natasha_Volkova [10]

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12,400

Step-by-step explanation:

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7 0
3 years ago
Help please and thank you!
Usimov [2.4K]

Answer:

Option A

Explanation:

\rightarrow \sf sin\left(\dfrac{7\pi }{6}\right)

\rightarrow \sf \sin \left(\pi +\dfrac{\pi }{6}\right)

\rightarrow \sin \left(\pi \right)\cos \left(\dfrac{\pi }{6}\right)+\cos \left(\pi \right)\sin \left(\dfrac{\pi }{6}\right)

\rightarrow \sf 0 *  \dfrac{\sqrt{3}}{2}+\left(-1\right) * \dfrac{1}{2}

\rightarrow \sf -\dfrac{1}{2}

7 0
2 years ago
What are the real zeroes of x3 + 6 x2 – 9x - 54?
o-na [289]

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of x^3+6x^2-9x-54

Solving

x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)

Taking x^2 common from first 2 terms and -9 from last two terms we get

=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\

Taking (x+6) common

(x+6)(x^2-9)\\

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

=(x+6)((x)^2-(3)^2)\\=(x+6)(x+3)(x-3)

Putting it equal to zero,

(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\,  x=3

So, Option B 3,-3,-6 is correct.

7 0
3 years ago
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