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3 years ago

The number of zeroes at the end of the cube root of the number1000

Mathematics

2 answers:

liubo4ka [24]3 years ago

6 0

The answer would be 10

ivolga24 [154]3 years ago

3 0

Hey there!

The answer to your question is one zero.

To solve this, we can first start by finding the cube root.

$\sqrt[3]{1000}$

The answer to this is $10$ , because $10 * 10 * 10 = 1000$

Now, we can see that there is one zero at the end of $10$ .

Hope it helps and have a great day/night! Stay safe!

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Describe the graph of a quadratic function below given in table form

Kipish [7]

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2 years ago

Greg has 245 cows on his farm. In the mornings, he gives them a total of 5,752 pounds of hay. If each cow eats the same amount,

Mashutka [201]

Answer:

I would say A because the real answer is 23.477

Step-by-step explanation:

5 0

3 years ago

Simplify each.Assume that none of the variables is zero.

Zanzabum

Answer:

2. 1 / a^2

3, 1

4. - 1

Step-by-step explanation:

Formulas : -

x^y / x^z = x^( y - z )

x^-y = 1 / x^y

x^y / x^y = 1

a^2 / a^4

= a^( 2 - 4 )

= a^-2

= 1 / a^2

m^6 / m^6 = 1

- 8^4 / 8^4

= - 1 x 8^4 / 7^4

= - 1

3 0

2 years ago

Use the identity (x+y)(x2−xy+y2)=x3+y3 to find the sum of two numbers if the product of the numbers is 28, the sum of the square

fgiga [73]

Answer:

Step-by-step explanation:

1) f(x) = x+y , xy = 49 --> f(x) = x+49/x

f '(x) = 1-49/x2 , x = ±√49 , choose x = +7

y = 49/x = 7

smaller = 7

larger = 7

2) Vertical Distance is difference between the two functions

V(x) = x+56 - x2, V '(x) = 1 -2x --> x = 1/2 --> V(1/2) = 56.25 <---Max Vertical distance

Boundary at -7 and 8 are less

3) I googled the equation, it is really y(n) = kn/(49+n2)

y '(n) = (k(49+n2) - 2kn2)/(49+n2) , Setting to zero, k(49+n2) -2kn2 = 0 , n = 7

4) Let x and y be the sides of the rectangle. A = xy = 37.5 Million or y = 37.5/x

The length of the fences is f(x) = 2x + 3y = 2x+112.5/x

f '(x) = 2-112.5/x2 --> x = √56.5 = 7.5 and y = 37.5/7.5 = 5 then scale by √Million

smaller = 5000 ft and larger = 7500 ft

this took me ages to work out so hopefully it helped

4 0

2 years ago

Read 2 more answers

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

7 0

3 years ago