The answer us A.
Line AC needs to be congruent to DF because for SAS (side angle side) we have a side (BA and DE) and an angle (A and D) so we need another side.
Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
x
+
6
y
=
5
6
x
+
2
y
=
8
x
−
y
+
4
=
8
Use the given functions to set up and simplify
2
.
x
y
=
−
1
=
3
=
−
1
=
2
=
0
−
4
=
−
4
4
=
−
4
2
=
−
4
Step-by-step explanation:
Find the equation with a point and y-intercept.
y
=
(
y/
x − y
) x + x
y
The chosen topic is not meant for use with this type of problem. Try the examples below.
(
0
,
9
) , (
8
,
6
)
(
0
,
9
) , (
5
,
4
) , (
1
,
4
)
(
1
,
2
) , (
3
,
4
)
Answer:
x = 20
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Using ΔAHC , then
∠ACH = 180 - (2x + 100) = 180 - 2x - 100 = 80 - 2x
∠ECD = ∠ACB ( vertical angles are congruent ), thus
∠ECD = ∠ACH + ∠HCB, that is
3x = 80 - 2x + x
3x = 80 - x ( add x to both sides )
4x = 80 ( divide both sides by 4 )
x = 20
4 + 10 = 2 x 2 + 2 x 5 = 2 x (2 + 5)
Answer:
table C represents a linear function.