Answer: 2.9 m/s
Explanation:
The frequency of the beat is 4 Hz
The relative Doppler frequency is 235 + 4 = 239 Hz
We would be solving this question, using the formula for Doppler's effect
f(d) = f(v+vr)/(v-vs), where
F = 235 Hz
F(d) = 239 Hz
v = 344 m/s and vr = vs
239 = 235 (344 + vr) / (344 - vr)
239 ( 344 - vr) = 235 (344 + vr)
82216 - 239 vr = 80849 + 235 vr
82216 - 80849 = 235 vr + 239 vr
1376 = 474 vr
vr = 1376/474
vr = 2.9 m/s
Thus the speed the platform should move is 2.9 m/s
Answer:1. INCREASE 2. DECREASE 3. DECREASE
Explanation:
Answer:
5J/mol
Explanation:
H-H eclipsed = Torsional strain = 4.0 kJ/mol
H-CH3 eclipsed = Mostly torsional strain = 6.0 kJ/mol
CH3-CH3 eclipsed =Torsional and steric strain = 11.0 kJ/mol
CH3-CH3 gauche = Steric strain = 3.8 kJ/mol
You know each H-H eclipsed is 4 kJ/mol (8 kJ/mol total) and the reported barrier is 13 kJ/mol. Therefore the H-I eclipsed interaction must be 5 kJ/mol, (13-8 = 5).
Answer:
Explanation:
First, it is required to model the function that models the increasing force in the +x direction:
The equation is:
The impulse done by the engine is given by the following integral:
![Imp = 161.333\,\frac{N}{s^{2}}\cdot [(3.50\,s)^{3}-(2\,s)^{3}]](https://tex.z-dn.net/?f=Imp%20%3D%20161.333%5C%2C%5Cfrac%7BN%7D%7Bs%5E%7B2%7D%7D%5Ccdot%20%5B%283.50%5C%2Cs%29%5E%7B3%7D-%282%5C%2Cs%29%5E%7B3%7D%5D)
