Answer:
The phenomenon known as "tunneling" is one of the best-known predictions of quantum physics, because it so dramatically confounds our classical intuition for how objects ought to behave. If you create a narrow region of space that a particle would have to have a relatively high energy to enter, classical reasoning tells us that low-energy particles heading toward that region should reflect off the boundary with 100% probability. Instead, there is a tiny chance of finding those particles on the far side of the region, with no loss of energy. It's as if they simply evaded the "barrier" region by making a "tunnel" through it.
Explanation:
Answer: Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. These waves are generated by radioactive atoms and in nuclear explosions. Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells.
Explanation: :)
Answer:
moment of inertia is 2.72 kg m²
Explanation:
given data
mass m = 10kg
height h = 4.5 m
radius r = 0.5 m
speed v = 6.5 m/s
to find out
moment of inertia
solution
we apply here conservation of energy
that is
mgh = 1/2 ×mv² + 1/2 × Iω²
here I is moment of inertia we find and
we know ω = Velocity / radius = 6.5 / 0.5 = 13
and g = 9.8
so put here all these value
10 (9.8) 4.5 = 1/2 ×(10)(6.5)² + 1/2 × I(13)²
441 = 211.25 + 1/2 × I( 169 )
I = 2.72
so moment of inertia is 2.72 kg m²
Answer:
The magnitude will be "353.5 N". A further solution is given below.
Explanation:
The given values is:
F = 500 N
According to the question,
In ΔABC,
⇒ 
⇒ 
then,
⇒ 
⇒ 
Now,
The corresponding angle will be:
⇒ 
⇒ 
⇒ 
Aspect of F across the AC arm will be:
= 
On putting the values of F, we get
= 
= 
Component F along the AC (in magnitude) will be:
= 
= 
= 
When the temperature of 0.50 kg of water decreases by 22 °C, the energy transferred to the surroundings from the water is -46.2 kJ.
A sample of 0.50 kg of water boils (reaches 100 °C). After a while, its temperature decreases by 22 °C.
We can calculate the energy transferred to the surroundings from the water in the form of heat (Q) using the following expression.
where,
- c: specific heat capacity of water
- m: mass of water
- ΔT: change in the temperature
When the temperature of 0.50 kg of water decreases by 22 °C, the energy transferred to the surroundings from the water is -46.2 kJ.
Learn more: brainly.com/question/16104165
