Given that a car is in the road, there is only movement in the x-direction. There is no movement in the y-direction.
Looking at the y-direction for the normal force:
F = N - mg
0 = N - mg, (no movement in y-dir.)
N = mg
N = (990)(9.8)
N = 9702 newtons
The normal force exerted on the car by the road is 9702 newtons.
So there are different ways this could be solved. I'll do try to explain it the way I was taught...
Simon is riding his bike at 12 km/hr relative to the sidewalk, away from where Keesha is.
Simon throws the ball at Keesha, at 5 km/hr.
Keesha sees the ball approaching her at (12-5) = 7 km/hr relative to the ground to her.
Therefore the answer is: 7 km/hr
First, we have a change in the velocity from 85 to 164 m/s in 10 sec.
Then, we calculate the <u>acceleration </u>as:
Hence we need to calculate the velocity of the space vehicle at t = 2 sec using the first equation of motion:
Then, using the second equation of motion to calculate the distance:
according to the second law of dynamics F = m • a => a = F / m
The answer is slightly left and slightly right of the curved end of the horseshoe.
