Answer:
the final velocity of the object is 53.04 m/s.
Explanation:
Given;
initial velocity of the projectile, u = 50 m/s
displacement of the object, d = 16 m
let the final velocity of the object = v
Apply the following kinematic equation to determine the final velocity of the projectile.
v² = u² + 2gd
v² = 50² + (2 x 9.8 x 16)
v² = 2813.6
v = √2813.6
v = 53.04 m/s
Therefore, the final velocity of the object is 53.04 m/s.
The nucleus of an atom is about 10-15 m in size; this means it is about 10-5 (or 1/100,000) of the size of the whole atom. A good comparison of the nucleus to the atom is like a pea in the middle of a racetrack. (10-15 m is typical for the smaller nuclei; larger ones go up to about 10 times that.)
Q before connected = Q after connected C1V1+C2V2 = (C1+C2) V
C1= 3×10^-6 F
V1= 480v
C2= 4×10^-6 F
V2= 500v
(3×10^-6)×(480) + (4×10^-6)×(500) = (3×10^-6 + 4×10^-6) × V
Simplifying the above, we get:
( 1440× 10^-6) + (2000 ×10^-6) = (7 × 10^-6) × V.
Further simplified as:
3440 × 10^-6 = 7 × 10^-6 × V
Making V the subject
V = 491.43volts
Therefore the potential difference across each capacitor is 491.43v
Heat required = mass (g)*specific heat (c)* Temperature change (ΔT)
Given,
mass = 150 g, specific heat = 4.187 J/g.K, ΔT = -15 -(-30 = -15+30 = 15 K
Therefore,
Heat, H = 150*4.187*15 = 9420.75 J
Unusual precipitation patterns