Answer:
The magnitude of force exerted on the handle is 108.73 N
Explanation:
To determine the magnitude of force exerted, we will use the formula relating Power and Force.
Power is the rate at which work is done. Power can be calculated from the formula
Power = Work / Time
But, Work = Force × Distance
Hence,
Power is given by the formula
Where P is the Power
F is the force
s is the distance
and t is the time
From ,
Then we can write that
From the question,
Distance, s = 1.1 m
Time, t = 1.3 s
Power, P = 92 W
Putting these values into the formula, we get
Hence, the magnitude of force exerted on the handle is 108.73 N.
I believe it would be 60*3.5. I apologize if this information is wrong.
Answer:
Answer:
PLEASE BRAINLESS ME INEED
# CARRY ON LEARNINGAnswer:
PLEASE BRAINLESS ME INEED
# CARRY ON LEARNING
Answer
given,
initial velocity of the ball, u = 40 m/s
final velocity of the ball, v= -40 m/s
time of contact = 0.013 s
mass of the ball = 0.059 Kg
a) initial momentum
P₁ = m u = 0.059 x 40 = 2.36 kg.m/s
final momentum
P₂ = m v = 0.059 x (-40) = -2.36 kg.m/s
b) change in momentum
Δ P = P₂- P₁
Δ P = -2.36 - 2.36
Δ P = -4.72 kg.m/s
c) Average force
average force exerted by the ball is equal to change in momentum per unit time.
F = -363 N
It is given that,
Mass of the object, m = 0.5 kg
A force is applied for 27 ms.
Initial speed of the object, u = +14 m/s
Impulse of the force, J = 32.4 N-s (in negative direction)
Let v is the velocity of mass in x direction. We know that the impulse of an object is equal to the change in momentum. It is given by :
v = -67 m/s
So, the velocity of the mass is 67 m/s and it is in negative x direction.
