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iVinArrow [24]
3 years ago
15

Answer the following question below.

Mathematics
1 answer:
kotykmax [81]3 years ago
3 0
If I’m right I think the answer is 1,759.32
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What is the quotient of 4 divided by 9/10
kozerog [31]
The answer is 49/9 because you can first convert the fraction into a decimal and devide 4 and 0.9 and you will get 5.4 repeating and which is 49/9
3 0
4 years ago
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Halp me plss halp me
ZanzabumX [31]

Answer:

14m

Step-by-step explanation:

To find the diagonal length of the triangle, your formula will be a² + b² = c²

the side length is a

and the base length is b

6 + 8 = 14

You have been halped

5 0
2 years ago
myra swims 3/5 of a mile farther than luke.if luke swims 2 and 4/10 miles, how many milrs does myra swim?
Irina-Kira [14]
The answer is 447 because you got to add 35 plus 410
3 0
3 years ago
12.
Andrews [41]

Answer:

9.9 inches

Step-by-step explanation:

The area of a triangle is given by

A = 1/2 bh  where b is the length of the base and h is the length of the height

49 = 1/2 x*x

Multiply each side by 2

2*49 = x^2

98 = x^2

Take the square root of each side

sqrt(98) = sqrt(x^2)

9.899494937 =x

Rounding to the nearest tenth

9.9 =x

5 0
3 years ago
Read 2 more answers
In the trapezoid ABCD (AB∥CD) point M∈AD, so that AM:MD=3:5. Line L ∥AB and going through point M intersects diagonal AC and leg
siniylev [52]

Answer:

\dfrac{AP}{PC}=\dfrac{3}{5}

\dfrac{BN}{CN}=\dfrac{3}{5}

Step-by-step explanation:

Consider triangles AMP and ADC. In these triangles,

  • angle A is the common angle, so \angle MAP\cong \angle DAC by reflexive property;
  • angles AMP and ADC are congruent as corresponding angles when two parallel lines MP and CD are cut by transversal AD.

Hence, triangles AMP and ADC are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

\dfrac{AM}{AD}=\dfrac{AP}{AC}\\ \\\dfrac{3x}{3x+5x}=\dfrac{AP}{AC}\\ \\\dfrac{AP}{AC}=\dfrac{3}{8}\Rightarrow AP=\dfrac{3}{8}AC\\ \\PC=AC-AP=AC-\dfrac{3}{8}AC=\dfrac{5}{8}AC,

so

\dfrac{AP}{PC}=\dfrac{\frac{3}{8}AC}{\frac{5}{8}AC}=\dfrac{3}{5}

Consider triangles ACB and PCN. In these triangles,

  • angle C is the common angle, so \angle ACB\cong \angle PCN by reflexive property;
  • angles ABC and PCN are congruent as corresponding angles when two parallel lines PN and AB are cut by transversal BC.

Hence, triangles ACB and PCN are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

\dfrac{CP}{AP}=\dfrac{CN}{CB}\\ \\\dfrac{5x}{3x+5x}=\dfrac{CN}{CB}\\ \\\dfrac{CN}{CB}=\dfrac{5}{8}\Rightarrow CN=\dfrac{5}{8}CB\\ \\BN=BC-CN=BC-\dfrac{5}{8}BC=\dfrac{3}{8}BC,

so

\dfrac{BN}{CN}=\dfrac{\frac{3}{8}BC}{\frac{5}{8}BC}=\dfrac{3}{5}

4 0
3 years ago
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