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iVinArrow [24]
3 years ago
15

Answer the following question below.

Mathematics
1 answer:
kotykmax [81]3 years ago
3 0
If I’m right I think the answer is 1,759.32
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Percy delivers pizzas for pizza king. He is paid $6 an hour plus $2.50 for each pizza he delivers. Percy earned $280 last week.
Triss [41]
Hey You!

6 × 30 = 90

280 - 90 = 190

190 / 2.50 = 76

We can check using multiplication.

2.50 × 76 = 190

Percy delivered 76 pizzas.
7 0
3 years ago
kayla took $36.75 to the state fair. each ticket in the fair cost x dollars. kayla bought 3 tickets. write an expression that re
Gennadij [26K]
F(x)=y=the amount of money, in dollars , that Kad had after she bought the tickets.
x=price of one ticket

f(x)=-3x+36.75     or  y=-3x+36.75
7 0
3 years ago
A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq
Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

s=16.6 represent the sample deviation

\bar X=12.8 represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

\alpha=1-0.99=0.01 represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448

12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

3 0
3 years ago
Whats 567 divided by 566789
Doss [256]

0.00100037227 will be your correct answer.

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3 years ago
Hey can anyone help me with 6th grade homework
Liula [17]
All depends on what help you need
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3 years ago
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