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3 years ago

10

PLEASE HELP

1 answer:

zzz [600]3 years ago

5 0

$(x,\ y)\\\text{Put the values of x and y to the inequality}\ 3y-4x\geq-6\\\\A.\ (-3,\ 8)\\3(8)-4(-3)\geq-6\\24+12\geq-6\\36\geq-6\qquad TRUE\\\\B.\ (5,\ 10)\\3(10)-4(5)\geq-6\\30-20\geq-6\\10\geq-6\qquad TRUE\\\\C.\ (1,\ 2)\\(3)(2)-(4)(1)\geq-6\\6-4\geq-6\\2\geq-6\qquad\ TRUE\\\\D.\ (-5,\ 2)\\(3)(2)-(4)(-5)\geq-6\\6+20\geq-6\\26\geq-6\qquad TRUE\\\\Answer:\ a,\ b,\ c\ and\ d\ are\ solutions\ of\ this\ inequality.$

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3 years ago

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zzz [600]

Answer:

a)

$P(X = 0) = 0.64$

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$P(X = 2) = 0.25$

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Step-by-step explanation:

We have these following probabilities:

64% = 0.64 probability that he misses both shots, that is, makes none of them.

11% = 0.11 probability that he makes one shot.

25% = 0.25 probability that he makes both shots.

a. Construct the appropriate probability distribution. (Round your answers to 2 decimal places.)

Binomial probability distribution, in which P(X = x) is the probability of making x shots. So

$P(X = 0) = 0.64$

$P(X = 1) = 0.11$

$P(X = 2) = 0.25$

b. What is the probability that he makes no more than one of the shots? (Round your answer to 2 decimal places.)

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0.75 = 75% probability that he makes no more than one of the shots

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3 years ago