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Sladkaya [172]
3 years ago
10

PLEASE HELP

Mathematics
1 answer:
zzz [600]3 years ago
5 0

(x,\ y)\\\text{Put the values of x and y to the inequality}\ 3y-4x\geq-6\\\\A.\ (-3,\ 8)\\3(8)-4(-3)\geq-6\\24+12\geq-6\\36\geq-6\qquad TRUE\\\\B.\ (5,\ 10)\\3(10)-4(5)\geq-6\\30-20\geq-6\\10\geq-6\qquad TRUE\\\\C.\ (1,\ 2)\\(3)(2)-(4)(1)\geq-6\\6-4\geq-6\\2\geq-6\qquad\ TRUE\\\\D.\ (-5,\ 2)\\(3)(2)-(4)(-5)\geq-6\\6+20\geq-6\\26\geq-6\qquad TRUE\\\\Answer:\ a,\ b,\ c\ and\ d\ are\ solutions\ of\ this\ inequality.

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Answer:

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Step-by-step explanation:

This involves trigonometry. Since we need to find the value of a, we need to find a trig equation with a as the numerator. Luckily, we have one, tan. So, tan(20) is equal to a/6, right. So, using a calculator, tan(20) is approximately equal to 0.363. This times 6 should equal a. This is approximately around 2.1. Thus our answer is 2.1

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How do I solve this math question ?
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Here we will use algebra to find three consecutive integers whose sum is 300. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 300. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 300

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

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Which means that the first number is 99, the second number is 99 + 1 and the third number is 99 + 2. Therefore, three consecutive integers that add up to 300 are 99, 100, and 101.

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We know our answer is correct because 99 + 100 + 101 equals 300 as displayed above.

Step-by-step explanation:

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