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Lostsunrise [7]
3 years ago
7

Which of the graphs below would result if you made the leading term of the

Mathematics
2 answers:
shutvik [7]3 years ago
4 0

Answer:

its b just did it hop this helps

Anettt [7]3 years ago
3 0

Answer:

A%7.2= ( 7.5№) =(+--+) this is the best answer

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Consider that a 1/2 cup of serving of 1% cottage cheese is equivalent to 125 grams. If one once of cottage cheese is equivalent
Andre45 [30]

Answer:

4.4 ounces

Step-by-step explanation:

125/28.35 to find how many ounces can fit into 125 grams since 28.35 is one ounce. the answer is 4.4 so 4 2/5 (or 4.4) ounces is a half cup serving

7 0
3 years ago
Find the general solution for cos x = 0, where n is an integer.
Romashka-Z-Leto [24]
First we solve this equation:
x = cos^-1(0) = pi/2 and 3pi/2

Now, this is the answer for angles between 0 and 2pi

but there are "negative angles" and angles larger than 2pi
so the general solution that includes all of these cases is:

x = pi/2 + n*pi

here n is any integer.
6 0
3 years ago
Find the midpoint of the segment connecting (4,7) to (-2,3).
KonstantinChe [14]
If you put 2 points on a graph paper and connect them, you can find the midpoint pretty easily
8 0
2 years ago
The state of Colorado is in the shape of a rectangle whose length is 380 miles and whose length is 380 miles and whose width is
KiRa [710]
Area of a rectangle is Length times width
So basically 380 * 280 should be the answer
The answer should be 106400
8 0
3 years ago
Read 2 more answers
What is the equation of this graphed line?
barxatty [35]

Answer:

y=-\frac{1}{3}x-5

Step-by-step explanation:

Given:

The two points on the line are:

(x_1,y_1)=(-6,-3)\\(x_2,y_2)=(6,-7)

Now, for a line with two points on it, the slope of the line is given as:

m=\frac{y_2-y_1}{x_2-x_1}

For the points (x_1,y_1)=(-6,-3)\ and\ (x_2,y_2)=(6,-7), slope is:

m=\frac{-7-(-3)}{6-(-6)}\\m=\frac{-7+3}{6+6}\\m=\frac{-4}{12}=-\frac{1}{3}

Now, for a line with slope 'm' and a point (x_1,y_1) on it is given as:

y-y_1=m(x-x_1)

Plug in all the values and determine the equation of the line. This gives,

y-(-3)=-\frac{1}{3}(x-(-6))\\\\y+3=-\frac{1}{3}(x+6)\\\\y+3=-\frac{1}{3}x-\frac{1}{3}\times 6\\\\y+3=-\frac{1}{3}x-2\\\\y=-\frac{1}{3}x-2-3\\\\y=-\frac{1}{3}x-5

Therefore, the equation of the line is:

y=-\frac{1}{3}x-5

4 0
3 years ago
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