Help!! 10 points!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Point (-12 , 8) is on the line that passes through (0, 6) and is parallel to the given line ⇒ 1st
Step-by-step explanation:
Parallel lines have:
- Same slopes
- Different y-intercepts
The formula of the slope of a line which passes through points and
is
∵ The given line passes through points (-12 , -2) and (0 , -4)
∴ = -12 ,
= 0
∴ = -2 ,
= -4
- Use the formula of the slope above to find the slope of the given line
∵
∴ The slope of the given line is
∵ The two lines are parallel
∴ Their slopes are equal
∴ The slope of the parallel line =
∵ The parallel line passes through point (0 , 6)
- The form of the linear equation is y = mx + b, where m is the slope
and b is the y-intercept (y when x = 0)
∵ m = and b = 6
∴ The equation of the parallel line is y = x + 6
Let us check which point is on the line by substitute the x in the equation by the x-coordinate of each point to find y, if y is equal the y-coordinate of the point, then the point is on the line
Point (-12 , 8)
∵ x = -12 and y = 8
∵ y = (-12) + 6
∴ y = 2 + 6 = 8
- The value of y is equal the y-coordinate of the point
∴ Point (-12 , 8) is on the line
Point (-12 , 8) is on the line that passes through (0, 6) and is parallel to the given line
Learn more:
You can learn more about the equations of parallel lines in brainly.com/question/9527422
#LearnwithBrainly
To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3. 2g of AlCl3 contains 9.034*10^21 molecules.
<h3>Number of Molecules in 2g of AlCl3</h3>The molar mass of AlCl3 is given as 133.34g/mol
Data;
- mass = 2g
- molar mass = 133.34g/mol
Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.
If we equate this
From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.
Learn more on mole concept here;
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