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zepelin [54]
3 years ago
13

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE I BEGGING YOUPLZ

HELP plz show your work ( 77 POINTS)
1. 1/4 ÷ 2 1/4


2. Solve and graph the solution to each inequality below.

2(3y-2)>8


3. Solve and graph the solution to the inequality below.

2(k-1)>-2.2


4. Solve and graph the solution to the inequality below.

4x+24≤ 32


5. Solve and graph the solution to the inequality below. 5n+5>-45
Mathematics
1 answer:
MAXImum [283]3 years ago
6 0

Answer 1 -16 3y-2 >16 k-1 >24 -8.8x>24-8.8x<32

Step-by-step explanation:

k>3, x> - 10-11,y>2-3 (128k-127)

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In circle F with the measure of minor arc EG = 122, finh m
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Answer:

MEASURE OF F WILL BE 58°

Step-by-step explanation:

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3 years ago
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Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0
natita [175]

Answer:

\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

Step-by-step explanation:

Given differential equation,

(x^2 + y^2) dx + (x^2 - xy) dy = 0

\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)

Let y = vx

Differentiating with respect to x,

\frac{dy}{dx}=v+x\frac{dv}{dx}

From equation (1),

v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}

v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}

v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}

v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}

x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v

x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}

x\frac{dv}{dx}=\frac{v+1}{v-1}

\frac{v-1}{v+1}dv=\frac{1}{x}dx

Integrating both sides,

\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx

\int{\frac{v-1+1-1}{v+1}}dv=lnx + C

\int{1-\frac{2}{v+1}}dv=lnx + C

v-2ln(v+1)=lnx+C

Now, y = vx ⇒ v = y/x

\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

5 0
3 years ago
1. A plumber cut a pipe into 6 identical pieces. Each piece measures 17.4 feet long.
iragen [17]

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Step-by-step explanation:

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A researcher testing seed varieties for tulips got a confidence interval of (14.2%,17.4%) for the percent of seeds that can grow
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Answer:

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In a confidence interval of proportions, we have the lower bound and the upper bound of the interval. The sample proportion is the halfway points between these bounds, that is, the sum of these bounds divided by 2.

In this problem, we have that:

Lower bound: 0.142

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Sample proportion: (0.142+0.174)/2 = 0.158

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You buy 2 packages of ground beef. One package contains 4.5 pounds and the other contains 2.25 pounds. Your put equal amounts of
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