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3 years ago

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Maisie has three times as many CDs as Ken. ken has twice as many CDs as Jo. Jo has more than 10 CDs. What is the least number of

CDs that Masie can have?

1 answer:

STatiana [176]3 years ago

3 0

Answer:

Least number is 60.

Step-by-step explanation:

Let the number of CDs has Jo be represented by x + 10. Where x = 0, 1, 2, 3....

Then, since Ken has twice as many CDs as Jo, the number of CDs that Ken has can be expressed as;

2(x + 10) = 2x + 20

Maisie has three times as many CDs as Ken, then the number of CDs that Maisie has can be expressed as;

3(2x + 20) = 6x + 60

Thus to determine the least number of CDs that Maisie can have, let x = 0.

3(2x + 20) = 6x + 60

= 6(0) + 60

= 60

Therefore, the least number of CDs that Maisie can have is 60.

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svetoff [14.1K]

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$f(1)=10$ and $f(n)=f(n-1)-4$ .

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