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dem82 [27]
3 years ago
8

How to solve the following equation: 5²(2x-3)=100

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
6 0
The answer is x=7/2 or 3.5
Y_Kistochka [10]3 years ago
6 0
5^2 = 25, 25 • 2x = 50x, 25 • 3 = 75

That gives you 50x - 75 = 100

100 - 75 = 25

That gives you 50x = 25

25/50 = 0.5

Final answer x = 0.5
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Find the sum of 3x + 2,5x- 7 and - 3 + 2x ​
lions [1.4K]

Step-by-step explanation:

the answer is 10x - 8.

3x+2

5x-7

2x-3

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10x-8

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6 0
3 years ago
Complete the table of values for the function f(x) = (1/3)x for a, b, and c. x : -2, -1, 0, 1, 2. f(x) : a, b, c, 1/3, 1/9
balu736 [363]

Given:

The function is

f(x)=\left(\dfrac{1}{3}\right)^x

To find:

The missing values for a, b, and c in the given table.

Solution:

We have,

f(x)=\left(\dfrac{1}{3}\right)^x

At x=-2,

f(-2)=\left(\dfrac{1}{3}\right)^{-2}

a=\left(3\right)^{2}         \left[\because \left(\dfrac{a}{b}\right)^{-n}=\left(\dfrac{b}{a}\right)^{n}\right]

a=9

At x=-1,

f(-1)=\left(\dfrac{1}{3}\right)^{-1}

b=\left(3\right)^{1}         \left[\because \left(\dfrac{a}{b}\right)^{-n}=\left(\dfrac{b}{a}\right)^{n}\right]

b=3

At x=0,

f(0)=\left(\dfrac{1}{3}\right)^{0}

c=1         \left[\because a^0=1, a\neq 0\right]

Therefore, the missing values of a,b and c are 9, 3, and 1 respectively.

8 0
3 years ago
Read 2 more answers
What is 1+1-(3x3)-(1x9)
vodomira [7]
1+1-(3x3)-(1x9)
The answer is -16
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