Answer:
1,888 pencils
Step-by-step explanation:
Answer:
what is your question because I'm not sure if u accidentally forgot to put the question up
Step-by-step explanation:
Hope I'm able to help you later with your question
Question 1: C. (-4, 8]
With B, I think you assumed since there are two separate lines for the function, there must be two separate ranges. Additionally, you state that the left one has a range from -4 to 3, each non-inclusive, which is incorrect as there is a solid point at y = 3. However, the -4 non-inclusive part is correct.
Basically, this is all one function therefore there should be a single range. Since as you can see on the graph, 8 is included, the new range should be (-4, 8]. The function extends from -4, non-inclusive, to 8, inclusive. Even though there is a gap between the two parts, it is a singular function and as a whole, both are considered when calculating the range.
Question 2: C, {x | x > 10}
You are correct! x = 10 is a vertical asymptote for this function - the function will never reach this value so you should not use the "greater than or equal to" sign.
Answer:
19, 58 and 103
Step-by-step explanation:
Okay. Here we need to convert whatever statements we have into a mathematical expression.
Firstly, let’s give the smallest angle a value of x. Where do we now go from here? The measure of one angle is 1 degree greater than 3 times the size of the smallest angle. This means the value of the second angle is 3x + 1
Now for the third angle, the question stated that the third angle is thirteen degrees less than twice the measure of the second angle. The value for this is: 2( 3x + 1) - 13
Now when we add all these angles, surely, we get a result equal to 180.
x + 3x + 1 + 2(3x + 1) - 13 = 180
4x + 1 + 6x + 2 - 13 = 180
10x - 10 = 180
10x = 190 and x = 19.
Now the measure of the other angles are as follows:
3x + 1 = 3(19) + 1 = 57 + 1 = 58
2(3x + 1) - 13 = 2(58) - 13 = 103
Answer:
g(x)= x+1
Step-by-step explanation:
Given ![f(x)= \sqrt[3]{x+2}](https://tex.z-dn.net/?f=f%28x%29%3D%20%5Csqrt%5B3%5D%7Bx%2B2%7D)
, ![f(x)= \sqrt[3]{x+3}](https://tex.z-dn.net/?f=f%28x%29%3D%20%5Csqrt%5B3%5D%7Bx%2B3%7D)
![f(g(x))= \sqrt[3]{x+3}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%20%5Csqrt%5B3%5D%7Bx%2B3%7D)
Replace x with g(x)
![f(g(x))= \sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%20%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
Now we need to find out what we plug in for g(X) to get x+3 under the radical
g(x) +2 is under the radical. we need x+3 , so we replace g(x) with x+`
So g(x)+2 becomes x+1+2 is x+3
Hence g(x) is x+1
