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sveta [45]
2 years ago
11

An arithmetic sequence a starts 2, 5, . .

Mathematics
1 answer:
Whitepunk [10]2 years ago
6 0

Answer:

Tn = 3n-1

T6 = 17

Step-by-step explanation:

Given the arithmetic sequence;

2, 5...

first term a = 2

Common difference d = 5-2 = 3

nth term of an AP is expressed as Tn = a + (n-1)d

Tn = 2 + (n-1)(3)

Tn = 2 + 3n-3

Tn = 3n-1

Get the 6th term

T6 = 3(6)-1

T6 = 18-1

T6 = 17

Hence the 6th term of the sequence is 17

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3 years ago
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Nostrana [21]

Answer:

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Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

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Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

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