3 years ago

PLEASE HELP Due Soon!

Physics

1 answer:

lakkis [162]3 years ago

5 0

It’s transferred thru ur brain

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2.<br> ___ ___ is the number of wavelengths that pass a given point/second.

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Answer:

frequency tell me if im right

Explanation:

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The answer will be 137 mL

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What is the quality of the sound of a fire truck’s siren when it moves toward a stationary hearer?

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What is the quality of the sound of a fire truck’s siren when it moves away from a stationary hearer?

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3 years ago

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In Fig., block 1 of mass m1 slides from rest along a frictionless ramp from height h = 2.50 m and then collides with stationary

Evgesh-ka [11]

Answer:

Explanation:

Given

initial height $h=2.5 m$

$m_2=2m_1$

coefficient of static friction $\mu =0.5$

When collision is elastic respective velocities after collision is

$v_1=\frac{u_1(m_1-m_2)+2m_2u_2}{m_1+m_2}$

$v_2=\frac{u_2(m_2-m_1)+2m_1u_1}{m_1+m_2}$

where $u_1$ and $u_2$ =initial velocities of object

$v_1$ and $v_2$ final velocities of object

$u_1=\sqrt{2\times 9.8\times 2.5}$

$u_1=7 m/s$

$v_2=\frac{0+2m_1\times 7}{m_1+2m_1}$

$v_2=\frac{14}{3} m/s$

using $v^2-u^2=2 as$

$0-(4.67)^2=2\times (-0.5\times 9.8)\times s$

$s=2.22\ m$

(b)Completely Inelastic

In Completely Inelastic objects stick with each other

$m_1u_1=(m_1+m_2)v$

$v=\frac{u_1}{3}=\frac{7}{3} m/s$

using $v^2-u^2=2 as$

$0-(2.33)^2=2\times (-0.5\times 9.8)\times s$

$s=0.55\ m$

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4 years ago

An athlete stretches a spring an extra 40.0 cm beyond its initial length. how much energy has he transferred to the spring, if t

marissa [1.9K]

The energy transferred to the spring is given by:
$U= \frac{1}{2}kx^2$
where
k is the spring constant
x is the elongation of the spring with respect its initial length

Let's convert the data into the SI units:
$k=52.9 N/cm = 5290 N/m$
$x=40.0 cm=0.4 m$

so now we can use these data inside the equation ,to find the energy transferred to the spring:
$U= \frac{1}{2}kx^2= \frac{1}{2}(5290 N/m)(0.4m)^2=423.2 J$

4 0

3 years ago