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andrew-mc [135]
3 years ago
11

If you have 18 students and all are paired up at least once how many projects in the year

Mathematics
2 answers:
devlian [24]3 years ago
5 0
9. A pair is two. 18 divided by two is 9.
KatRina [158]3 years ago
4 0
It would be 9 because you get half the number of projects because 18 students are partners and if you divide that you would have 9 groups of 2 and if you multiply that by the number of projects you would get the number of projects (ex:18 dividend by 2 it's 9 then if there is three projects assigned you multiply 9 by 3 to get 27 projects got it?
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A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot
Olegator [25]

Answer:

The ratio of the drag coefficients \dfrac{F_m}{F_p} is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, c_{m} = The drag coefficient of the prototype, c_{p}

The medium of the test for the model, \rho_m = The medium of the test for the prototype, \rho_p

The drag force is given as follows;

F_D = C_D \times A \times  \dfrac{\rho \cdot V^2}{2}

We have;

L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m

Therefore;

\dfrac{L_p}{L_m}  = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2

\dfrac{L_p}{L_m}  =\dfrac{17}{1}

\therefore \dfrac{L_p}{L_m}  = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{c_p \times A_p \times  \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times  \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}

\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3

\dfrac{F_m}{F_p}  = \left( \left\dfrac{1}{17} \right)^3= (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients \dfrac{F_m}{F_p} ≈ 0.0002.

5 0
3 years ago
Solve the equation for t A=s(t+r)x
tester [92]

Answer:

t = (A/sx) - r

Step-by-step explanation:

Solve for t like this:

A = s(t+r)x\\A = sx(t+r)\\\\\frac{A}{sx} = t+r\\\frac{A}{sx} - r = t\\t= \frac{A}{sx} - r

6 0
3 years ago
X 6.4.5-T
butalik [34]

Same strategy as before: transform <em>X</em> ∼ Normal(76.0, 12.5) to <em>Z</em> ∼ Normal(0, 1) via

<em>Z</em> = (<em>X</em> - <em>µ</em>) / <em>σ</em>   ↔ <em>X</em> = <em>µ</em> + <em>σ</em> <em>Z</em>

where <em>µ</em> is the mean and <em>σ</em> is the standard deviation of <em>X</em>.

P(<em>X</em> < 79) = P((<em>X</em> - 76.0) / 12.5 < (79 - 76.0) / 12.5)

… = P(<em>Z</em> < 0.24)

… ≈ 0.5948

8 0
3 years ago
A swim meet has 13 contestants signed up for the 100-meter butterfly event. The first heat has 6 swimmers. How many different wa
tino4ka555 [31]

Answer:

6 swimmers in the first heat can be arranged in 1716 different ways.

Step-by-step explanation:

A swim meet has 13 contestants signed up. To calculate the arrangement of first 6 swimmers in first heat we will use combinations because order doesn't matter.

So to select 6 swimmers out of 13 contestants number of different ways

= ^{13}C_{6}

= \frac{13!}{(6!)(13-6)!}

= \frac{13\times 12\times 11\times 10\times 9\times 8\times 7!}{6!\times 7!}

= \frac{13\times 12\times 11\times 10\times 9\times 8}{6\times 5\times 4\times 3\times 2\times 1}

= \frac{1235520}{720}

= 1716

Therefore, 6 swimmers in the first heat can be arranged in 1716 different ways.

5 0
3 years ago
4/7 of students at a school are boys. If there are 2723 students at the school, how many are girls?
zloy xaker [14]
4/7= 0.571
2723 x 0.571= 1554
6 0
3 years ago
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