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3 years ago

6 x (8 - 3) = (? x 8) - (? x 3) what are the answers for the question marks?

Mathematics

2 answers:

soldier1979 [14.2K]3 years ago

7 0

The answer is 6.

THey are using distributive property.

6 x (8-3) = 30. 6x5=30.

6 x 8 equals 48. 6 x 3 equals 18. 48-18 equals 30.

Please tell me if I am wrong, and hope it helps!

Elina [12.6K]3 years ago

3 0

6 x (8 - 3) =

(6 x 8) - (6 x 3)

The answer is 6

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Steve wants to buy a new music player. The player he wants costs $279.95. The city he lives charges a 5% sales tax, so for every

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Ultimately, the question is "What is 5% of $279.95?"

To answer this, multiply 279.95 by 5%, or 0.05 which is 5% in decimal form.

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2 years ago

Mr. Zillow wants to research the prices in a Subdivision near Disney World called World of Homes. The prices of 14 homes in this

ExtremeBDS [4]

Answer:

Looking for four values or answers

(A) 5.05

(B) 13

(D) $254,145.38

Step-by-step explanation:

(A) The value of the margin of error.

Using a 90% confidence level or 0.10 alpha level,

1 - alpha = 1 - 0.10 = 0.90

The degrees of freedom = n - 1 = 14 - 1 = 13

Using the t table, 0.90 under 13 is 1.350

Sample size divided by √n is equal to

14/√14 = 3.742

1.35 × 3.742 = 5.05

(B) 13 degrees of freedom

(C) To find the lower and upper limits, you find the mean value first and then subtract / add to half of the margin of error which is 5.05÷2 = 2.525

Adding the 14 values together, you have $3,558,000

Dividing by 14 to get the mean;

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4 0

3 years ago

A sphere is inscribed in a cube with a surface area of 216 square centimeters. What is the volume of the sphere

pentagon [3]

Answer:

$V=298.5cm^3$

Step-by-step explanation:

To find the volume of the sphere we need to know its radius.

And the radius can be found with the information we have about the surface area.

The formula for the surface area is as follows:

$SA=4\pi r^2$

from this formula we clear the radius r:

$r^2=\frac{SA}{4\pi}\\ \\r=\sqrt{\frac{SA}{4\pi} }$

and we substitute the known value of the surface area, and also the value of $\pi$ :

$r=\sqrt{\frac{216cm^2}{4(3.1416)} }\\ \\r=\sqrt{\frac{216cm^2}{12.5664} }\\ \\r=\sqrt{17.1887cm^2}\\ \\r=4.146cm$

and now that we know the radius we find the volume:

$V=\frac{4\pi r^3}{3} \\\\V=\frac{4(3.1416)(4.146cm)^3}{3}\\ \\V=\frac{895.521cm^3}{3}\\ \\V=298.5cm^3$

the volume of the sphere is $298.5cm^3$

7 0

3 years ago

which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

3 years ago

For the function f(x) = x + 7, what is the ordered pair for the point on the graph when x = 2b. A. ( 2b, 2b+7). B. ( 2b, x + 7).

Fynjy0 [20]

$f(2b)=2b+7\\\\
(2b,2b+7)$

6 0

3 years ago

Read 2 more answers