First you find how much the shape has dilated. To d ok that you divide the size of the size already given to you from the bigger shape from the same did if the smaller shape. So 58÷6=9.7. The shape grew by 9.7. To find x you use the similar side of the other shape again and multiy that size by 9.7. So 9.7×3=29.1
x=29.1
Start by reviewing your knowledge of natural logarithms. If we take the ln of both sides we get e^z=ln(1). Do the same thing again and wheel about the ln(ln(1)). There's going to be complex solutions, Wolfram Alpah gets them but let me know if you figure out how to do it?
Hi there
a/(a² - 36) + 2/(a-6) = 1/(a+6)
a/(a+6)(a-6) + 2/(a-6) = 1/(a+6)
Now we need to multiply the terms by (a+6)(a-6)
a + 2(a+6) = 1(a-6)
a + 2a + 12 = a - 6
3a + 12 = a - 6
3a - a = -6 - 12
2a = -18
Divide both sides by 2
2a/2 = -18/2
a = -9
Thus, The correct option is A
I hope that's help !
Good luck !
5.37796e13 please don't waste our time.
