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ira [324]
3 years ago
13

I really dont get it halp ;-;

Mathematics
2 answers:
erik [133]3 years ago
6 0

Answer:

II

Step-by-step explanation:

This would be easier to explain to you on a graph, but I shall do the best I can in text format.

You know what a complex plane looks like, right? Just like a number line but with a vertical number line added on at the point (0). This makes four quadrants, you know the drill.

So each quadrant holds all values from on of the four positive/negative combinations, (1, 1i), (1, -1i), (-1, -1i), and (-1, 1i), in that order.

So this means that all the pairs with both positive values are in quadrant I, all the pairs with a positive rational number but a negative irrational number are in II, etc.

If you have a graph, you can simply count along the number line to find the answer, so in this case, starting as always at (0, 0), move 6 units to the right and then eight units down, where you end up in the lower righthand quadrant, which is II.

Oof I know that was worded badly but I hope it's not totally useless to you <3

You're doing great with the test, Gem, I'm sure you'll do just fine <:

Advocard [28]3 years ago
4 0

Answer:

IV

HOPE IT HELP IT WILL YOU❣️

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Answer:

D. 68 (APEX).........................................................................................

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3 years ago
Please help me with problem 22a I dont understand how to find the rate of change
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The rate of change is x2. So, since it's forty, it became 80 because 40x2=80!
         Good luck for a good grade!
5 0
3 years ago
Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti
spayn [35]

Answer:

(a)D(x)=-2,500x+60,000

(b)R(x)=60,000x-2500x^2

(c) x=12

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500

Therefore, we have:

y=-2500x+b

At point (12,30000)

30000=-2500(12)+b\\b=30000+30000\\b=60000

Therefore:

D(x)=-2,500x+60,000

(b)Revenue

R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0

Therefore:

  • Optimal ticket price:$12
  • Maximum Revenue:$360,000

3 0
3 years ago
All similar figures are congruent. Give a counterexample to disprove this conjecture.
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Two equilateral triangles, but one has sides measuring 3 cm, while the other measures 6 cm. The figures are similar, but not congruent
7 0
2 years ago
Y = – 2x² + 12x - 7
Vikentia [17]

Answer:

a) axis of symmetry: <em> </em><em>x</em> = <em>h</em>

b) Vertex: (3, 11).

c/d) Maximum point = vertex (3, 11).

Step-by-step explanation:

<em><u>Note:</u></em><em> </em>This post will only provide the answers for parts a through d, in accordance with Brainly's Guidelines.

Given the quadratic equation, y = – 2x² + 12x - 7, where a = -2, b = 12, and c = -7:

<h3>  </h3><h3>a) What is equation of the axis of symmetry?</h3>

The <u>axis of symmetry</u> is an imaginary line that divides the graph of a parabola into two symmetrical parts.  The axis of symmetry goes through the x-coordinate of the vertex, (<em>h</em>, k). Hence, the axis of symmetry is often represented by the following equation: x = h.  

<h3 /><h3>b) What is the vertex?</h3>

We can find the x-coordinate of the vertex by using the following formula:

\displaystyle\mathsf{x\:=\:\frac{-b}{2a}}

Substitute the given values for a = -2, and b = 12 into the formula:

\displaystyle\mathsf{x\:=\:\frac{-(12)}{2(-2)}\:=\:\frac{-12}{-4}\:=\:3}

Hence, the x-coordinate of the vertex is 3.  

Substitute x = 3 into the given quadratic equation to find its corresponding y-coordinate:

y = – 2x² + 12x – 7

y = – 2(3)² + 12(3) – 7

y = –2(9) + 36 – 7

y = – 18 + 36 – 7

y = 11

Therefore, the <u>vertex</u> of the given quadratic equation is (3, 11).

<h3 /><h3>c/d) Does the equation have a maximum or minimum? What is the maximum/minimum?</h3>

The value of the "<em>a</em>" coefficient in the quadratic equation, y = <u>a</u>x² + bx + c, determines whether a given parabola has either a minimum, or a maximum.

  • If <em>a</em> > 1, then it means that the graph of a parabola opens <u>upward</u>, and the vertex is its <u><em>minimum</em></u> point.
  • If <em>a</em> < 0, then the graph of a parabola opens downward, and the vertex is its <u><em>maximum</em></u> point.  

Since the value of our given quadratic equation is a = -2, then it means that its graph opens <em>downward</em>, and that the <u>vertex is its maximum point</u>.  

Attached is a screenshot of the graph, where it shows the vertex occurring at point (3, 11), for which the axis of symmetry goes through at x = 3.

5 0
2 years ago
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