mark creates a flower bed that is semicircular in shape as shown on the image. the diameter of the flower is 5 meter

1 answer:

5 0

Ok so take 5 and divide that by 2 then whatever answer u get multiply that times 3.14 and are u solving for circumference

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In a study of academic procrastination, the authors of a paper reported that for a sample of 471 undergraduate students at a mid

AnnZ [28]

Answer:

95% confidence interval for the mean time spent studying for the final exam for students taking introductory psychology at this university is [6.85 hours, 7.43 hours].

Step-by-step explanation:

We are given that a sample of 471 undergraduate students at a midsize public university preparing for a final exam in an introductory psychology course, the mean time spent studying for the exam was 7.14 hours and the standard deviation of study times was 3.20 hours.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean time spent studying for the exam = 7.14 hours

$\sigma$ = population standard deviation = 3.20 minutes

n = sample of undergraduate students = 471

$\mu$ = population mean time

Here for constructing 95% confidence interval we have used One-sample z test statistics.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $7.14-1.96 \times {\frac{3.20}{\sqrt{471} } }$ , $7.14+1.96 \times {\frac{3.20}{\sqrt{471} } }$ ]

= [6.85 hours , 7.43 hours]

Therefore, 95% confidence interval for the mean time spent studying for the final exam for students taking introductory psychology at this university is [6.85 hours, 7.43 hours].

7 0

3 years ago

Giving people brainlyiest, to whoever gets it right.

Yuliya22 [10]

Answer:

I think it might be D

Step-by-step explanation:

if you use the formula A(t) = P(1+r)^t

Then plug in 950(1+0.0376)^4 and solve it comes out to 1101. 14 so it should be D

7 0

2 years ago

Evaluate y5 for y = 1. 1 5 15