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3 years ago

mark creates a flower bed that is semicircular in shape as shown on the image. the diameter of the flower is 5 meter

1 answer:

5 0

Ok so take 5 and divide that by 2 then whatever answer u get multiply that times 3.14 and are u solving for circumference

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In a town election ,Azeem got 42 percent of the vote cast and Hamza get the remaining votes . If the total number of votes cast

sveta [45]

Answer:

23,200

Step-by-step explanation:

percentage of vote in favor of Azeem = 42

Since total percentage is 100

and Hamza got remaining percentage points

it can be calculated by subtracting Azeem's percentage of vote from total percentage

mathematically we have

percentage of vote in favor of Hamza = total percentage of vote - percentage of vote in favor of Azeem = 100 - 42 = 58

Therefore Hamza got 58% votes

Total no of votes cast as given in problem = 40,000

Vote for Hamza = 58% of total votes = 58% of 40000

=>Vote for Hamza = (58/100) * 40000 = 23,200.

Votes obtained by hamza is 23,200

8 0

3 years ago

Is 25.789 bigger then 25.879

dimulka [17.4K]

It is not bigger. 25.879 is bigger by .100

6 0

3 years ago

14. Ms. Brooks cell phone plan charges $27.00 a month for her phone. She is charged $0.15 per text she sends. She sends 78 texts

Licemer1 [7]

Answer:

$27.00 + 0.15t =

Step-by-step explanation:

8 0

3 years ago

Find the length of the third side if necessary round to the nearest tenth

Fantom [35]

Answer:

Step-by-step explanation:

Let's call the missing side as x

Base on the pythagorean theorem, we have :
17² - 15² = x²

289 - 225 = x²

x² = 64

So, x equals 8.

Hope it helps

8 0

3 years ago

part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.

andreev551 [17]

Answer: $\bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}$

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>

$5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: (15)² + (3√11)² = hypotenuse² → hypotenuse = 18

$6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}$

Note: 8² + 15² = hypotenuse² → hypotenuse = 17

$7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}$

Note: hypotenuse not needed for tan

$8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}$

Note: 2² + 6² = hypotenuse² → hypotenuse = 2√10

8 0

3 years ago