Answer:
c=f(x)−ax^2−bx
Step-by-step explanation:
Equation of a circle is:
<span>(x−h<span>)2</span>+(y−k<span>)2</span>=<span>r2</span></span>
h is the x-coordinate of the center and k is the y-coordinate of the center. Even though the formula has minus signs, those are positive numbers. If there were plus signs in there, the numbers h and k would actually be negative. Now since you're centered at the origin, that means h and k are 0, so you'd just have this:
<span><span>x2</span>+<span>y2</span>=<span>r2</span></span><span>
Now since your radius is 7, just square it and replace r^2 woth that value :)</span>
9514 1404 393
Answer:
- -√5
- 3/5
- -4/5
Step-by-step explanation:
The relevant relations are ...
sec = ±√(tan² +1)
cos = 1/sec
csc = 1/sin = ±1/√(1 -cos²)
Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.
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1. sec(θ) = -√((-2)² +1) = -√5
2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5
3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5
