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Stolb23 [73]
2 years ago
6

I can’t find the percent someone plz help

Mathematics
1 answer:
liraira [26]2 years ago
4 0
what percent? can you attach a photo
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During the first decade of the century, the population of a certain city was 145,380 in 2000 and 219,135 in 2010. Find the expon
Likurg_2 [28]

Answer:

The exponential growth function is P=145380e^{0.04103t}

Step-by-step explanation:

Given: The population of a certain city was 145,380 in 2000 and 219,135 in 2010.

To find: exponential growth function that models the growth of the city

Solution:

The exponential growth function is given by P=P_0 e^{kt}

Here, P denotes total population after time t

P_0 denotes initial population

k denotes rate of growth

t denotes time

As P(0)=145,380,

145380=P_0e^{0}\\145380=P_0\\P=145380e^{kt}

As P(10)=219135

219135=145380e^{10k}\\e^{10k}=\frac{219135}{145380}\\=1.507326\\k=\frac{1}{10}\ln (1.507326)\\=0.04103\\\Rightarrow P=145380e^{0.04103t}

8 0
2 years ago
8. Mr. Gardner is contemplating which shullle service to take lo the airport. Fost
Lisa [10]

Answer:

Frosts second mile and steadys 6th mike

Step-by-step explanation:

5 0
2 years ago
Find the common factor and rewrite.
Tju [1.3M]

Answer:

 8A + 11A  = A(19)

Step-by-step explanation:

   8A + 11A

 = A(8 + 11)                      Factor out the common factor A

= A(19)

 

7 0
2 years ago
A store is having a sale on chocolate chips and walnuts. For 3 pounds of chocolate chips and 5 pounds of walnuts, the total cost
umka21 [38]

c = cost per pound of chocolate chips

w = cost per pound of walnuts.

\bf \stackrel{\textit{3 lbs of "c"}}{3c}+\stackrel{\textit{5 lbs of "w"}}{5w}~~=~~\stackrel{\textit{costs}}{15} \\\\\\ \stackrel{\textit{12 lbs of "c"}}{12c}+\stackrel{\textit{2 lbs of "w"}}{2w}~~=~~\stackrel{\textit{costs}}{33} \end{cases}\qquad \impliedby \textit{let's use elimination} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{llccccccl} 3c+5w=15&\times (-4)\implies &-12c&+&-20w&=&-60\\ 12c+2w=33&&12c&+&2w&=&33\\ \cline{3-7}\\ &&0&&-18w&=&-27 \end{array}

\bf -18w=-27\implies w=\cfrac{-27}{-18}\implies \blacktriangleright w=\cfrac{3}{2} \blacktriangleleft \\\\\\ \stackrel{\textit{substituting on the 1st equation}}{3c+5\left(\cfrac{3}{2} \right)=15}\implies 3c+\cfrac{15}{2}=15 \implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2\left( 3c+\cfrac{15}{2} \right)=2(15)} \\\\\\ 6c+15=30\implies 6c=15\implies c=\cfrac{15}{6}\implies \blacktriangleright c=\cfrac{5}{2} \blacktriangleleft

6 0
3 years ago
Nicolas has $650 to deposit into two different savings accounts. • Nicolas will deposit $400 into Account I, which earns 3.5% an
OLga [1]

account 1:

$400 * 0.035 * 2 = $28

$28 interest earned so total = $400 + $28 = $428

account 2:

<span>A = P(1+r/n)^(nt)</span>

= $250(1+0.035)^2 = 267.50

total account 1 and account 2 =

$428 + $267.81 = $695.50

answer is B $695.00


4 0
3 years ago
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