Answer:
area = 6x^2+10x-4 perimeter= 5x+3
Step-by-step explanation:
10 crayons = $5
1 crayon = $5 ÷ 10 = $0.50
Answer: Unit Price = $0.50/crayon
Answer:
15
Step-by-step explanation:
If the other triangle is part of the problem the triangle increased by 2.5
2.5 * 6 is 15
so 15 is the length of TR
If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
Answer:
a)
, b)
.
Step-by-step explanation:
a) The graphic is enclosed to the problem. By visual inspection, an absolute maximum is found.
![P (x,y) \approx (0.1,1.05)](https://tex.z-dn.net/?f=P%20%28x%2Cy%29%20%5Capprox%20%280.1%2C1.05%29)
b) The exact method consists in the application of the First and Second Derivative Tests. First and second derivatives are, respectively:
![f'(x) = 1 - 14\cdot x](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%201%20-%2014%5Ccdot%20x)
![f''(x) = -14](https://tex.z-dn.net/?f=f%27%27%28x%29%20%3D%20-14)
The First Derivative Test consists in equalizing the first derivative to zero and solving the expression:
![1 - 14\cdot x = 0](https://tex.z-dn.net/?f=1%20-%2014%5Ccdot%20x%20%3D%200)
![x = 0.07](https://tex.z-dn.net/?f=x%20%3D%200.07)
According to the second derivative, the critical point leads to a maximum. The remaining component is determined by evaluation the polynomial:
![y = 1 +0.07-7\cdot (0.07)^{2}](https://tex.z-dn.net/?f=y%20%3D%201%20%2B0.07-7%5Ccdot%20%280.07%29%5E%7B2%7D)
![y = 1.04](https://tex.z-dn.net/?f=y%20%3D%201.04)
The exact solution is
, indicating that graphic solution leads to a good approximation.