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Vaselesa [24]
3 years ago
15

1.20×10−8s to nanoseconds

Chemistry
1 answer:
AveGali [126]3 years ago
7 0

Answer:

There are 12 nanoseconds in 1.2\times 10^{-8}\ s.

Explanation:

We need to convert 1.2\times 10^{-8}\ s to nanoseconds.

We know that,

1\ s=10^9\ ns

Now using unitary method to solve it such that,

1.2\times 10^{-8}\ s=1.2\times 10^{-8}\ \times 10^9\\\\=1.2\times 10\\\\=12\ ns

So, there are 12 nanoseconds in 1.2\times 10^{-8}\ s.

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4 0
3 years ago
PLEASE HELP!
Mice21 [21]

Answer:

The Axis Powers took these aggressive actions prior to the outbreak of World War II which include the invasion of Ethiopia, Manchuria, and the Rhineland.

Explanation:

Axis Powers: It was the coalition of Germany, Italy and Japan against the <em>Allied Powers</em> (the United States, the Soviet Union, Great Britain, and China) in World War II.

  1. In 1930, the Japanese took control of railway track in Manchuria (a region in China) and in  1931, the Japan attacked the Chinese army claiming that the Chinese soldiers sabotaged the railway.
  2. On 3 October 1935, Italy invaded the Ethiopia (former name: Abyssinia) in the leadership of <em>Mussolini </em>to expand its territories.
  3. Germany in the leadership of Adolf Hitler occupied the Rhineland in 1937 by making excuse that the area is hostile and dangerous for them.  

5 0
3 years ago
SOMEONE PLEASE HELP
Zinaida [17]

Answer:

6. 7870 kg/m³ (3 s.f.)

7. 33.4 g (3 s.f.)

8. 12600 kg/m³ (3 s.f.)

Explanation:

6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.

1 kg= 1000g

1m³= 1 ×10⁶ cm³

Mass of iron bar

= 64.2g

= 64.2 ÷1000 kg

= 0.0642 kg

Volume of iron bar

= 8.16 cm³

= 8.16 ÷ 10⁶

= 8.16 \times 10^{ - 6} \:  kg

\boxed{density =  \frac{mass}{volume} }

Density of iron bar

=  \frac{0.0642}{8.16 \times 10^{ - 6} }

= 7870 kg/m³ (3 s.f.)

7.

\boxed{mass = density \:  \times volume}

Mass

= 1.16 ×28.8

= 33.408 g

= 33.4 g (3 s.f.)

8. Volume of brick

= 12 cm³

= 12  \times  10^{ - 6}  \: m^{3}  \\  = 1.2 \times 10^{ - 5}  \: m ^{3}

Mass of brick

= 151 g

= 151 ÷ 1000 kg

= 0.151 kg

Density of brick

= mass ÷ volume

=  \frac{0.151} {1.25 \times 10^{ - 5} }  \\  = 12600 \: kg/ {m}^{3}

(3 s.f.)

6 0
3 years ago
concentrated phosphoric acid is90% H3PO4 by mass and the remaining mass is water. The molarity of H3PO4 is 12.2M at temperature
blondinia [14]

Answer:

82.0 mL

Explanation:

Step 1: Given data

  • Concentration of concentrated acid (C₁): 12.2 M
  • Volume of concentrated acid (V₁): ?
  • Concentration of dilute acid (C₂): 1.00 M
  • Volume of dilute acid (V₂): 1.00 L

Step 2: Calculate the required volume of the concentrated acid

We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated acid using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.00 M × 1.00 L / 12.2 M = 0.0820 L = 82.0 mL

4 0
2 years ago
HCl, NaCl, and CO are all examples of chemical <br> properties<br> bonds<br> formulas<br> changes
Ainat [17]

Answer:

HCL, NACL and CO are the examples of chemical formulas

4 0
3 years ago
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