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Vaselesa [24]
2 years ago
15

1.20×10−8s to nanoseconds

Chemistry
1 answer:
AveGali [126]2 years ago
7 0

Answer:

There are 12 nanoseconds in 1.2\times 10^{-8}\ s.

Explanation:

We need to convert 1.2\times 10^{-8}\ s to nanoseconds.

We know that,

1\ s=10^9\ ns

Now using unitary method to solve it such that,

1.2\times 10^{-8}\ s=1.2\times 10^{-8}\ \times 10^9\\\\=1.2\times 10\\\\=12\ ns

So, there are 12 nanoseconds in 1.2\times 10^{-8}\ s.

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Consider the chemical equation below.
igor_vitrenko [27]

Answer : The net ionic equation will be,

2H^{+}(aq)+2OH^-(aq)\rightarrow H_2O(l)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

Mg(OH)_2(aq)+2HNO_3(aq)\rightarrow Mg(NO_3)_2(aq)+H_2O(l)

The ionic equation in separated aqueous solution will be,

Mg^{2+}(aq)+2OH^-(aq)+2H^{+}(aq)+2NO_3^{-}(aq)\rightarrow H_2O(l)+Mg^{2+}(aq)+2NO_3^{-}(aq)

In this equation, Mg^{2+}\text{ and }NO_3^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

2H^{+}(aq)+2OH^-(aq)\rightarrow H_2O(l)

7 0
3 years ago
What is acid, base give examples?​
Alinara [238K]

Answer:

Common examples include hydrochloric acid, sulfuric acid, citric acid and ethanoic acid. Bases are a group of substances that neutralise acids. Soluble bases are called alkalis.

Explanation:

Hope this helps.

8 0
2 years ago
What are the main organs for the respiratory system?
liubo4ka [24]

Answer:

lungs and blood vessels, airway

Explanation:

because the respiratory system are a system that helps people breate. the lungs breathe in oxygen and then breathe out carbon dioxide. the blood vessels carries the oxygen into the body to other part of the system in the body that needed oxygen to make glucose.

5 0
2 years ago
what is the molarity of an HCI solution if 25.0 ml of 0.185 M NaOH is required to neutralize 0.0200 L of HCI?​
butalik [34]

Answer:

Molarity of HCl solution = 0.25 M

Explanation:

Given data:

Volume of NaOH= V₁ = 25.0 mL (25/1000 = 0.025 L)

Molarity of NaOH solution=M₁ = 0.185 M

Volume of HCl solution = V₂ = 0.0200 L

Molarity of HCl solution =  M₂= ?

Solution:

M₁V₁   =  M₂V₂

0.185 M ×0.025 L =  M₂ × 0.0200 L

M₂  = 0.185 M ×0.025 L / 0.0200 L

M₂  = 0.005M.L /0.0200 L

M₂  =  0.25 M

7 0
2 years ago
D= Sx2
lbvjy [14]

Answer:

2160 times 4 would be the answer

Explanation:

Took it

7 0
2 years ago
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