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kvv77 [185]
3 years ago
14

A volleyball player hit a ball with a mass of 0.25 kg. The average acceleration of the ball is 15.5 m/s². How much force did the

volleyball player apply to the ball? 62.0 N 3.87 N 62.0 m/s² 3.87 m/s²
Chemistry
2 answers:
Law Incorporation [45]3 years ago
8 0

 

F=MA

0.25Kg.15.5M/S^2

= 3.875N


Inessa05 [86]3 years ago
4 0

<u><em>This should be in the Physics section...</em></u>

The formula which links mass, acceleration and force is:

F = ma

So to calculate the force applied, we can substitute the values from the question into the formula:

F = 0.25 \times 15.5 = 3.875 N

Thus, the answer is 3.875 N

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If 25.3 grams of mercury(II) oxide react to form 23.4 grams of mercury, how many grams of oxygen must simultaneously be formed?
sergij07 [2.7K]

Answer : The mass of oxygen formed must be 3.8 grams.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

2HgO\rightarrow 2Hg+O_2

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of 2HgO = Total mass of 2Hg+O_2

As we are given :

The mass of HgO = 25.3 grams

The mass of Hg = 23.4 grams

So,

2\times 25.3g=2\times 23.4g+\text{Mass of }O_2

50.6g=46.8g+\text{Mass of }O_2

\text{Mass of }O_2=3.8g

Therefore, the mass of oxygen formed must be 3.8 grams.

6 0
3 years ago
20. What is the area of a piece of metal foil that measures 43.9 cm by 29.21 cm? Express the answer to
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Answer:

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Which element has the smallest atomic radius? Fluorine, Iron, Phosphorous, Potassium
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7 0
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Clearing the specific heat of the unknown substance:

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c_e = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot 12.1^\circ C}{75\ g\cdot (-59.4)^\circ C} = \bf 13.07\frac{J}{g\cdot ^\circ C}
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