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kvv77 [185]
3 years ago
14

A volleyball player hit a ball with a mass of 0.25 kg. The average acceleration of the ball is 15.5 m/s². How much force did the

volleyball player apply to the ball? 62.0 N 3.87 N 62.0 m/s² 3.87 m/s²
Chemistry
2 answers:
Law Incorporation [45]3 years ago
8 0

 

F=MA

0.25Kg.15.5M/S^2

= 3.875N


Inessa05 [86]3 years ago
4 0

<u><em>This should be in the Physics section...</em></u>

The formula which links mass, acceleration and force is:

F = ma

So to calculate the force applied, we can substitute the values from the question into the formula:

F = 0.25 \times 15.5 = 3.875 N

Thus, the answer is 3.875 N

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he equation represents the combustion of sucrose. C12H22O11 + 12O2 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of oxy
xeze [42]

Answer:

The moles of sucrose that are available for this reaction is 0.0292 moles

Explanation:

Combustion is an specifyc reaction where the reactants react with O₂ in order to produce CO₂ and H₂O

This combustion is: C₁₂H₂₂O₁₁ + 12O₂  → 12CO₂ + 11H₂O

We have to conver the mass to moles, to find out the limiting reactant

10 g . 1 mol / 342 g = 0.0292 moles of sucrose

8 g . 1mol / 32g = 0.250 moles of O₂

The moles of sucrose that are available for this reaction is 0.0292 moles

Before we start to work with the equation we must find the limiting reactant. When you find it, you can do all the calculations.

6 0
3 years ago
Calculate the mass of NaCl needed to make 40% solution from 3kg of water ? Could you explain step by step please :-)
earnstyle [38]
Ok so 40 percent of 3000 grams which is 3 kg is 1200 grams 
So you would need 1.2kg or 1200 grams to make a 40% solution
3 0
3 years ago
Which of these elements could be used in industry to control electron flow?
anzhelika [568]

Answer:

the answer is calcium

Explanation:

6 0
3 years ago
Need help with 22 and 24<br>​
choli [55]

Answer:

22:

Formular:

atomic \: mass =  \frac{ \sum(isotopic \: mass \times \%abundance)}{100}  \\

substitute:

atomic \: mass =  \frac{(23.985 \times 78.70) + (24.986 \times 10.13) + (25.983 \times 11.17)}{100}  \\  \\  =  \frac{(1887.620) + (253.108) + (290.230)}{100}  \\  \\  =  \frac{2430.958}{100}  \\  \\ { \boxed{ \boxed{average \: atomic \: mass = 24.3 \: amu}}}

23:

<em>Same</em><em> </em><em>element</em><em> </em><em>is</em><em> </em><em>represented</em><em> </em><em>by</em><em> </em><em>same</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>protons</em><em>.</em><em> </em>

Answer:

6 protons. 6 protons

7 neutrons. 8 neutrons

6 electrons. 6 electrons

Note: <u>Atoms</u><u> </u><u>with</u><u> </u><u>same</u><u> </u><u>proton</u><u> </u><u>number</u><u> </u><u>but</u><u> </u><u>different</u><u> </u><u>mass</u><u> </u><u>number</u><u> </u><u>are</u><u> </u><u>called</u><u> </u><u>isotopes</u>

5 0
3 years ago
Read 2 more answers
One of the hydrates of MnSO4 is manganese(II) sulfate tetrahydrate . A 71.6 gram sample of MnSO4 4 H2O was heated thoroughly in
Dennis_Churaev [7]

Answer:

48.32 g of anhydrous MnSO4.

Explanation:

Equation of dehydration reaction:

MnSO4 •4H2O --> MnSO4 + 4H2O

Molar mass = 55 + 32 + (4*16) + 4((1*2) + 16)

= 223 g/mol

Mass of MnSO4 • 4H2O = 71.6 g

Number of moles = mass/molar mass

= 71.6/223

= 0.32 mol.

By stoichiometry, since 1 mole of MnSO4 •4H2O is dehydrated to give 1 mole of anhydrous MnSO4

Number of moles of MnSO4 = 0.32 mol.

Molar mass = 55 + 32 + (4*16)

= 151 g/mol.

Mass = 151 * 0.32

= 48.32 g of anhydrous MnSO4.

3 0
2 years ago
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