Question

A volleyball player hit a ball with a mass of 0.25 kg. The average acceleration of the ball is 15.5 m/s². How much force did the volleyball player apply to the ball? 62.0 N 3.87 N 62.0 m/s² 3.87 m/s²

Answer 1

 

F=MA

0.25Kg.15.5M/S^2

= 3.875N

Answer 2

This should be in the Physics section...

The formula which links mass, acceleration and force is:

$F = ma$

So to calculate the force applied, we can substitute the values from the question into the formula:

$F = 0.25 \times 15.5 = 3.875 N$

Thus, the answer is 3.875 N