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kvv77 [185]
3 years ago
14

A volleyball player hit a ball with a mass of 0.25 kg. The average acceleration of the ball is 15.5 m/s². How much force did the

volleyball player apply to the ball? 62.0 N 3.87 N 62.0 m/s² 3.87 m/s²
Chemistry
2 answers:
Law Incorporation [45]3 years ago
8 0

 

F=MA

0.25Kg.15.5M/S^2

= 3.875N


Inessa05 [86]3 years ago
4 0

<u><em>This should be in the Physics section...</em></u>

The formula which links mass, acceleration and force is:

F = ma

So to calculate the force applied, we can substitute the values from the question into the formula:

F = 0.25 \times 15.5 = 3.875 N

Thus, the answer is 3.875 N

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What is the ideal gas law
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Answer: Gases are complicated. They're full of billions and billions of energetic gas molecules that can collide and possibly interact with each other. Since it's hard to exactly describe a real gas, people created the concept of an Ideal gas as an approximation that helps us model and predict the behavior of real gases. The term ideal gas refers to a hypothetical gas composed of molecules which follow a few rules:

Ideal gas molecules do not attract or repel each other. The only interaction between ideal gas molecules would be an elastic collision upon impact with each other or an elastic collision with the walls of the container. [What is an elastic collision?]

Ideal gas molecules themselves take up no volume. The gas takes up volume since the molecules expand into a large region of space, but the Ideal gas molecules are approximated as point particles that have no volume in and of themselves.

If this sounds too ideal to be true, you're right. There are no gases that are exactly ideal, but there are plenty of gases that are close enough that the concept of an ideal gas is an extremely useful approximation for many situations. In fact, for temperatures near room temperature and pressures near atmospheric pressure, many of the gases we care about are very nearly ideal.

If the pressure of the gas is too large (e.g. hundreds of times larger than atmospheric pressure), or the temperature is too low (e.g.

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−200 Cminus, 200, start text, space, C, end text) there can be significant deviations from the ideal gas law.

Explanation:

7 0
2 years ago
Read 2 more answers
Calculate the amount of heat gained when one 250 gram bottle is heated from 25oC to 30oC. The specific heat of water is 4.18 J/g
Fed [463]

Answer:

5230J

Explanation:

Mass (m) = 250g

Initial temperature (T1) = 25°C

Final temperature (T2) = 30°C

Specific heat capacity (c) = 4.184J/g°C

Heat energy (Q) = ?

Heat energy (Q) = Mc∇T

Q = heat energy

M = mass of the substance

C = specific heat capacity

∇T = change in temperature = T2 - T1

Q = 250 × 4.184 × (30 - 25)

Q = 1046 ×5

Q = 5230J

The heat energy required to raise the temperature of 250g of water from 25°C to 30°C is 5230J

7 0
2 years ago
Read 2 more answers
Which of the following metals is most reactive?
g100num [7]
The answer is, D. Calcium
7 0
3 years ago
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A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a
Nata [24]

Answer:

There are present 5,5668 moles of water per mole of CuSO₄.

Explanation:

The mass of CuSO₄ anhydrous is:

23,403g - 22,652g = 0,751g.

mass of crucible+lid+CuSO₄ - mass of crucible+lid

As molar mass of CuSO₄ is 159,609g/mol. The moles are:

0,751g ×\frac{1mol}{159,609g} = 4,7052x10⁻³ moles CuSO₄

Now, the mass of water present in the initial sample is:

23,875g - 0,751g - 22,652g = 0,472g.

mass of crucible+lid+CuSO₄hydrate - CuSO₄ - mass of crucible+lid

As molar mass of H₂O is 18,02g/mol. The moles are:

0,472g ×\frac{1mol}{18,02g} = 2,6193x10⁻² moles H₂O

The ratio of moles H₂O:CuSO₄ is:

2,6193x10⁻² moles H₂O / 4,7052x10⁻³ moles CuSO₄ = 5,5668

That means that you have <em>5,5668 moles of water per mole of CuSO₄.</em>

I hope it helps!

5 0
3 years ago
Monodisperse polyacrylonitrile contains molecules with the general formula -(CH2CHCN)n-, where n is typically greater than 10,00
pentagon [3]

Answer:

7.68 × 10²⁴

Explanation:

Step 1: Calculate the mass of 1 molecule of the monomer CH₂CHCN

We will get the mass of the monomer by adding the masses of the elements.

mCH₂CHCN = 3 × mC + 3 × mH + 1 × mN

mCH₂CHCN = 3 × 12.01 amu + 3 × 1.01 amu + 1 × 14.01 amu = 53.07 amu

Step 2: Convert the mass of the monomer to grams

We will use the conversion factor 1 amu = 1.66 × 10⁻²⁴ g

53.07 amu × 1.66 × 10⁻²⁴ g/1 amu = 8.81 × 10⁻²³ g

Step 3: Calculate "n"

We will divide the mass of the polymer by the mass of the monomer.

n = 676.8 g / 8.81 × 10⁻²³ g = 7.68 × 10²⁴

6 0
3 years ago
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