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Anettt [7]
3 years ago
13

The graph shows the market for graphic t-shirts. What does the graph show about the relationship between a product and its price

Mathematics
1 answer:
Soloha48 [4]3 years ago
5 0

Answer:

As the amount of a product goes down, the price goes up. As the interest in a product goes up, the price goes up. As the interest in a product goes down, the price goes up.

Step-by-step explanation:

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What is the greatest common factors of 60w,34w^2,and 24w^4
andrew11 [14]

Answer: 2w

Step-by-step explanation:

The greatest common factor could also be referred to as the Highest common factor. Now

60w, 34w² and 24w⁴

Now let concert each to its factors

60 = 2 × 2 × 3 × 5 × w

34w² = 2 × 17 × w × w

24w⁴ = 2 × 2 × 2 × 3 × w × w × w × w

Therefore H.C.F or the greatest common factor

G.C.F = 2 × w

= 2w

4 0
3 years ago
Evaluate tan(cos^-1(-15/17))
IrinaK [193]

The answer is -8/15.  This is a for sure correct answer.

7 0
3 years ago
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Let B be the basis of P3 consisting of the Hermite polynomials in Exercise 21, and let p.t / D 7 ! 12t ! 8t 2 C 12t 3. Find the
Anastasy [175]

To calculate the relative vector of B we have to:

P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]

The coordenates of:

p(t)= 12t^3-8t^2-12t+7, with respect to B satisfy:

C_1(1)+C_2(2t)+C_3(-2+4t^2)+C_4(-12t+8t^3)= 7-12t-8t^2+12t^3

Equating coefficients of like powers of t produces the system of equation:

\left \{ {C_1-2C_3=7} \atop {2C_2-12C_4=-12} \right. \\\left \{ {{4C_3=-8} \atop {8C_4=12}} \right.

After solving this system, we have to:

C_1=3\\C_2= 3\\C_3= -2\\C_4= \frac{3}{2}

And the result is:

P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]

Learn more: brainly.com/question/16850761

4 0
3 years ago
F (x) = 3x^3 - 4x^2 + 6x and g (x) = 5x^3 + 2x^2 - 3x. What is f (x) - g (x)
nekit [7.7K]
9x2-1............................................................................
5 0
2 years ago
7th grade math help me plzzzz
Nataly_w [17]

Answer:

<h3>The correct answer is <u>D: -30</u></h3>
5 0
3 years ago
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