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2 years ago

Which equation represents a greater rate of change than the one shown in the graph below?

Mathematics

1 answer:

Rasek [7]2 years ago

7 0

Answer:

y = .75x + 1 or y= 3/4x +1

Step-by-step explanation:

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How can you write 52+(8+25) to make it easier to add?

Liono4ka [1.6K]

You can't really make it easier to add, but since the (8+25) is in parentheses you should add that first

52 + 33

Then add straight away

52 + (8+25) = 85

8 0

3 years ago

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IR = V (solve for R) *

VashaNatasha [74]

Answer:

R = $\frac{V}{I}$

Step-by-step explanation:

IR = V ( isolate R by dividing both sides by I )

R = $\frac{V}{I}$

6 0

2 years ago

In the diagram AB is parallel to CD. What is the value of X

aivan3 [116]

Answer:

B) 120

Step-by-step explanation:

6 0

3 years ago

Someone please help me with this<br><br>8 = 2-h / 7 [h]<br>

Alika [10]

Step-by-step explanation:

hope this helps you dear friend.

3 0

2 years ago

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A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee

katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

$^nC_r=\dfrac{n!}{(n-r)!r!}$

Given : Total multiple-choice questions = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= $^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84$

No. of ways to answer 4 open-ended problems

= $^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15$

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= $84\times15=1260$

Hence, the correct answer is option A) 1260

5 0

3 years ago