There are a total 40 cars
and there is x yellow cars
and there are nine times as much white cars (9x white cars) lol
so x+9x=40
simplify 10x=40
divide both sides by ten 10x/10=40/10
x=4
we are looking for the number of WHITE cars sooo we multiply by 9-
9x=36
how is this "hardddd" no offence*
sorry im a mean person
Answer:
√30
Step-by-step explanation:
We can find the value of x by using Euclidean theorem
x^2 = 3 × 10
if x^ = 30 then x = √30
Answer:
v > -25/p
r = -5 +7/3 w
Step-by-step explanation:
- pv + 40 < 65
Subtract 40 from each side
- pv + 40-40 < 65-40
-pv < 25
Divide each side by -p (remember to flip the inequality since we are dividing by a negative)
-pv/-p > 25/-p
v > -25/p
7w - 3r = 15
Subtract 7w from each side
7w-7w - 3r = 15-7w
-3r = 15-7w
Divide by -3
-3r/-3 = (15-7w)/-3
r = -5 +7/3 w
Okay, here we have this:
Considering the provided function, we are going to calculate the requested one-side limits, so we obtain the following:
