As it is given here
initial speed is
v_i = 6 m/s
After 4 seconds the final speed is
v_f = 14 m/s
so here we can use the formula of acceleration using kinematics
a = \frac{v_f - v_i}{t}
a = \frac{14 - 6}{4}
a = 2 m/s^2
so here it will accelerate at 2 m/s^2 rate.
Answer:
x(8x^3-3) should be your answer
We want to factor x²-11x+18
In order to factor it, we must find two numbers that add to -11 and multiply to 18.
We will go through the list of factors of 18:
1, 2, 3, 6, 9, 18
We see that 9 and 2 multiply to 18. But we want two numbers that add to -11, so we will simply put a negative sign in front of 9 and 2.
-9 and -2 still multiply to 18 and they add to -11, so now we can factor the expression:
x²-11x+18 = (x-2)(x-9)
Answer:
Well this is kinda confusing
Step-by-step explanation:
im explaining the best way I can.
for exp 10 to the power of four = 40
but 10 to the power of 0 is 10
This is because your not multiplying by anything. it's just a normal number. I'm sorry I don't know what I got at here but I hope it helps a little. I'm honestly really sorry.