Answer:
Step-by-step explanation:
Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.
(Two tailed test for variance )
Sample variance =480
We can use chi square test for testing of hypothesis
Test statistic = 
p value = 0.0100
Since p <0.05 our significance level, we reject H0.
The sample variance cannot be claimed as equal to 300.
Answer:
589
Step-by-step explanation:
l x w
19x11
5x31
5x45
589
Answer:
(x, x2 − 3x − 28) for all real numbers
Step-by-step explanation:
<span>c^2 + 5c - 14 = 0 </span>
<span>(c-2)(c+7) = 0 </span>
<span>c-2 = 0 or c+7 = 0 </span>
<span>c = 2 or c = -7 </span>
<span>c^2 - 2c - 15 = 0 </span>
<span>(c-5)(c+3) = 0 </span>
<span>c-5 = 0 or c+3 = 0 </span>
<span>c = 5 or c = -3</span>
The probability that a U.S. household selected at random has a computer and has Internet access will be 0.72. The C and I are independent events. Then the correct option is B.
<h3>What is probability?</h3>
Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
Approximately 80% of households in the United States have computers. Of those 80%, 90% have Internet access.
Then the probability that a U.S. household selected at random has a computer and has Internet access will be
P(C and I) = 0.80 × 0.90
P(C and I) = 0.72
Then the C and I are independent events.
Then the correct option is B.
More about the probability link is given below.
brainly.com/question/795909
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