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4 years ago

Help i forgot 3(x−4)≥−2x+3

Mathematics

2 answers:

alekssr [168]4 years ago

6 0

Answer:

The answer is x_> 3

Step-by-step explanation:

AVprozaik [17]4 years ago

5 0

Answer:

x≥3

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

3x−12≥−2x+3

Step 2: Add 2x to both sides.

3x−12+2x≥−2x+3+2x

5x−12≥3

Step 3: Add 12 to both sides.

5x−12+12≥3+12

5x≥15

Step 4: Divide both sides by 5.

≥

x≥3

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Factor the expression? 10y+15+25y

Yuliya22 [10]

Answer:

5(7y + 3)

Step-by-step explanation:

10y + 15 + 25y

= 5 x 2y = 10y

= 5 x 3 = 15

= 5 x 5y = 25y

= 5(2y + 3 +5y)

So, the answer is 5(7y + 3).

Hope this helps! :)

Also Symbolab is a good website/app to use it'll give the steps and answer.

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3 years ago

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lana66690 [7]

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3 years ago

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finlep [7]

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3 years ago

A bakery made 100 donuts, in the display case, 40/100 were chocolate, 3/10 were glazed and cinnamon. which fraction of the donut

Evgesh-ka [11]

57 of them were cinnamon.

Explanation:

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7 0

3 years ago

Suppose M is the midpoint of Segment AB, P is the midpoint of Segment AM, and Q is the midpoint of segment PM.

DerKrebs [107]

The coordinates of M, P and Q in terms of a and b are $M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$ , $P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$ and $Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$ , respectively.

In this question we are going to use definitions of vectors and product of a vector by a scalar. Based on the information given on statement, we have the following vectorial formulas:

Location of M

$\overrightarrow{AM} = \frac{1}{2}\cdot \overrightarrow{AB}$

$\vec M - \vec A = \frac{1}{2}\cdot \vec B - \frac{1}{2}\cdot \vec A$

$\vec M = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec B$

$M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$

Location of P

$\overrightarrow{AP} = \frac{1}{2}\cdot \overrightarrow{AM}$

$\vec P - \vec A = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec A$

$\vec P = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec M$

$\vec P = \frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B$

$P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$

Location of Q

$\overrightarrow{QM} = \frac{1}{2}\cdot \overrightarrow{PM}$

$\vec M - \vec Q = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec P$

$\vec Q = \frac{1}{2}\cdot \vec P - \frac{1}{2}\cdot \vec M$

$\vec Q = \frac{1}{2}\cdot \left(\frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B\right) -\frac{1}{2}\cdot \left(\frac{1}{2}\cdot \vec A + \frac{1}{2}\cdot \vec B\right)$

$\vec Q = \frac{1}{8}\cdot \vec A -\frac{1}{8}\cdot \vec B$

$Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$

We kindly invite to check this question on midpoints: brainly.com/question/4747771

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2 years ago