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Black_prince [1.1K]
3 years ago
9

I need this done rn plz help

Mathematics
1 answer:
My name is Ann [436]3 years ago
8 0

Answer:

answer for yes total, is 5, the answer for no total is 20, the total for junior is 17, and the total for senior is 8.

Step-by-step explanation:

What you do is you add the 2 values. for example, to find the total for the juniors, you would add 1 to 16.

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(3 − 13x − 7x2) − (5x2 + 12x − 10)
Brums [2.3K]
113 is the answer hope i help u
5 0
3 years ago
Read 2 more answers
A town has a population of 13,000 and grows at 5% every year what will the population be after 11 years to the nearest whole num
scoray [572]
This question is based on the concept of
amount of interest. Therefore, 22,234 would be
the population after 11 years, to the nearest
whole number.
Given:
A town has a population of 13000 and grows at
5% every year.
We need to determined the population after 11
years, to the nearest whole number.
We know that,
Formula =A = P(1+ r)
Where, p be the population. r is the rate and t is
the time.
P= 13000,
r= 5%
†= 11
Now put all these values in formula.
We get,
5
A = 13000(1 +
A
= 13000(1 + 0.05)11
A
= 1300022, 234.41(0.95)
5 0
2 years ago
Hillgrove High School plays 3 soccer games. The team loses 2 of those games. According to the tree diagram, how many ways could
nikitadnepr [17]
It can go three ways, I hope this helped ^^
5 0
3 years ago
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The solution set for the equation of a circle is all the_____ on the circle.
zalisa [80]
The answer to your question is ( points ).
5 0
1 year ago
Please Help Me! It’s Math! Please!
nadezda [96]

Answer:

D. About 800 years

Step-by-step explanation:

Use the half-life equation:

A = A₀ (½)ⁿ

where A is the final amount,

A₀ is the initial amount,

and n is the number of half-lives.

0.90A₀ = A₀ (½)ⁿ

0.90 = (½)ⁿ

To solve for n, take log of both sides:

log 0.9 = n log 0.5

n = (log 0.9) / (log 0.5)

n = 0.152

It takes 0.152 half-lives.  The half-life of carbon-14 is 5730 years.

0.152 × 5730 years = 871 years

The closest answer is D.

8 0
3 years ago
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