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Verdich [7]
3 years ago
5

An acidic solution containing 0.010 m la3 is treated with naoh until la(oh)3 precipitates. use the solubility product for la(oh)

3 to find the concentration of oh when la3 first precipitates. at what ph does this occur?
Chemistry
1 answer:
pogonyaev3 years ago
3 0
Given:

0.010 M la3 is treated with naoh


The solution to know what is the ph:

La (OH) 3 = La3+ + 3OH-

Ksp = [La3+] [OH-^3

2 X 10^-21 = (0.010 M) [OH-] ^ 3

[OH-] = (2 X 10 ^ -21 / 0.010) ^1/3

[OH-] = 2.63 x 10^-7 M 

= 5.85 x 10^-7 M

This occurs at pOH = 6.23 and pH = 7.77
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