Gold has 79 protons on the periodic table
<span>1.16 moles/liter
The equation for freezing point depression in an ideal solution is
ΔTF = KF * b * i
where
ΔTF = depression in freezing point, defined as TF (pure) ⒠TF (solution). So in this case ΔTF = 2.15
KF = cryoscopic constant of the solvent (given as 1.86 âc/m)
b = molality of solute
i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1.
Solving for b, we get
ΔTF = KF * b * i
ΔTF/KF = b * i
ΔTF/(KF*i) = b
And substuting known values.
ΔTF/(KF*i) = b
2.15âc/(1.86âc/m * 1) = b
2.15/(1.86 1/m) = b
1.155913978 m = b
So the molarity of the solution is 1.16 moles/liter to 3 significant figures.</span>
Answer:
Explanation:
Originally Rutherford thought that the particles would fly straight through the foil. However, he found that the particles path would be shifted or deflected when passing through the foil. This is due to the fact that like charges repel each other.
Answer: [H3O+] = 1.58x10-6 M
Explanation:
Answer:
6.25 mg
Explanation:
32 days equals 4 half lives for the iodine, since one half life is 8 days. So, the first half life goes from 100 to 50 mg, second from 50 to 25, third from 25 to 12.5, and fourth from 12.5 to 6.25