Question

4. Write an equation for the line that is parallel to the given line and that passes

Answer 1

Answer:

$y=\frac{5}{2}x-14$

Step-by-step explanation:

Hi there!

What we need to know:

• Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)
• Parallel lines always have the same slope

1) Determine the slope (m)

$y=\frac{5}{2}x-10$

In the given equation, $\frac{5}{2}$ is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of $\frac{5}{2}$. Plug this into $y=mx+b$:

$y=\frac{5}{2}x+b$

2) Determine the y-intercept (b)

$y=\frac{5}{2}x+b$

Plug in the given point (-6,-29) and solve for b

$-29=\frac{5}{2}(-6)+b$

Simplify -6 and 2

$-29=\frac{5}{1}(-3)+b\\-29=(5)}(-3)+b\\-29=-15+b$

Add 15 to both sides to isolate b

$-29+15=-15+b+15\\-14=b$

Therefore, the y-intercept is -14. Plug this back into $y=\frac{5}{2}x+b$:

$y=\frac{5}{2}x-14$

I hope this helps!