Answer:
a) 0.1353
b) 0.3679
Step-by-step explanation:
Let's start by defining the random variable T.
T : ''The time (in hours) required to repair a machine''
T ~ exp (λ)
T ~ exp (1)
The probability density function for the exponential distribution is
(In the equation I replaced λ = L)
With L > 0 and x ≥ 0
In this exercise λ = 1 ⇒
For a)
For b)
The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur
Answer:
The answer could be easier if you make a ratio and actual graph
Step-by-step explanation:
Answer:
The expected value of the safe bet equal $0
Step-by-step explanation:
If
is a finite numeric sample space and
for k=1, 2,..., n
is its probability distribution, then the expected value of the distribution is defined as
What is the expected value of the safe bet?
In the safe bet we have only two possible outcomes: head or tail. Woodrow wins $100 with head and “wins” $-100 with tail So the sample space of incomes in one bet is
S = {100,-100}
Since the coin is supposed to be fair,
P(X=100)=0.5
P(X=-100)=0.5
and the expected value is
E(X) = 100*0.5 - 100*0.5 = 0
Answer:
Step-by-step explanation:
2y = -x +9
3x - 6y = -15
The solution is the value of x and y that will make the two equations true in the same time.
3x-6y = -15; divide both sides by 3
x-2y = -5; substitute 2y for -x+9 because the first equation tell us they are equal
x-(-x+9) = -5; open parenthesis
x+x-9 = -5 ; add 9 to both sides and combine like terms
2x = -5 +9; 2x = 4; divide both sides by 2
x= 2
Substitute x for 2
2y = -x+9 ; 2y = -2 +9 ; 2y = 7; y = 7/2 = 3.5
Solution is (2, 3.5)