Answer:
50% probability that a randomly selected respondent voted for Obama.
Step-by-step explanation:
We have these following probabilities:
60% probability that an Ohio resident does not have a college degree.
If an Ohio resident does not have a college degree, a 52% probability that he voted for Obama.
40% probability that an Ohio resident has a college degree.
If an Ohio resident has a college degree, a 47% probability that he voted for Obama.
What is the probability that a randomly selected respondent voted for Obama?
This is the sum of 52% of 60%(non college degree) and 47% of 40%(college degree).
So

50% probability that a randomly selected respondent voted for Obama.
Answer:
a ≈ 14 or 6
Step-by-step explanation:
264 = π × a × (20 - a)
a(20 - a) =
≈ 84 (rounded off to nearest whole number)
Opening the brackets we get;
a² - 20a + 84 = 0
Applying the quadratic formula we get:
a ≈ 14 or 6
Let x be the length of a month on the other dimension. Since a year value is 365.242 days
We have 2 × 365.242 = 5 × x
It means that 5x = 730,484
and that x = 730,484 / 5 ≈ 146,1 days rounded to the decimal
This means that a month length in the other dimension is of roughly 146 days.. and If we assume that a month in the other dimension is of 30 days approximately, then one day length would be of 146,1 / 30 ≈ 4.87 days