Answer:
-3 1/3
Step-by-step explanation:
The quadratic
... y = ax² +bx +c
has its extreme value at
... x = -b/(2a)
Since a = 3 is positive, we know the parabola opens upward and the extreme value is a minimum. (We also know that from the problem statement asking us to find the minimum value.) The value of x at the minimum is -(-4)/(2·3) = 2/3.
To find the minimum value, we need to evaluate the function for x=2/3.
The most straightforward way to do this is to substitue 2/3 for x.
... y = 3(2/3)² -4(2/3) -2 = 3(4/9) -8/3 -2
... y = (4 -8 -6)/3 = -10/3
... y = -3 1/3
_____
<em>Confirmation</em>
You can also use a graphing calculator to show you the minimum.
Area of triangle= (base*hieght)/2
T=(5*6)/2=15
T=15
To the right of T = (4*8)/2 = 16
Triangle to the right of T=16
Y=(6*6)/2 = 18
Y=18
A=(5*7)/2 = 17.5
A=17.5
To the right of A = (7*7)/2 = 24.5
A=24.5
E = (6.4*8.5)/2 = 27.2
E = 27.2
I = (2.7*3.6)/2 = 4.86
I = 4.86
N = I cant read N
D = (19*17)/2 = 161.5
D = 161.5
Do you think you can complete the rest?
Answer:
Step-by-step explanation:
Rule:
Your problem:
Answer:
Step-by-step explanation:
answer 0.6 multiply 3 by 0.2 and you get 0.6! thats what i understood sorry if im rong
Answer:
42. acute
43. obtuse
Step-by-step explanation:
Obtuse: which one of the interior angles measures more than 90° degrees, then the rest are less than ninety.
Acute: all less than ninety and all different.
