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jek_recluse [69]
2 years ago
7

I need help with 53 × 1.2 ≈ And 2.1 × 82 ≈ _

Mathematics
1 answer:
Mrac [35]2 years ago
3 0
53x1.2=63.6 and 2.1x82=98.4
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Find the inverse function y=-5x+20
Nezavi [6.7K]

Answer:

y= \frac{-1}{5} x +4

Step-by-step explanation:

We can find the inverse function of this excercise, isolating X and then changing the variables.

y=-5x+20\\y-20=-5x\\\frac{y-20}{-5} =x\\

\frac{y}{-5}-\frac{20}{-5}  = x\\\frac{-1}{5}y+\frac{20}{5} =x\\ \frac{-1}{5}y+4 =x

And now we change the variables and we get the inverse function:

y= \frac{-1}{5} x +4

7 0
2 years ago
Pemdas, thank you! <br>(-8 × -6) -4² ​
Aleksandr-060686 [28]

Answer:

32

Step-by-step explanation:

(-8 × -6) - 4² ​

48 - 4²

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P - Parentheses

E - Exponents

M - Multiplication

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A - Addition

S - Subtraction

8 0
2 years ago
Read 2 more answers
A 2-kg sausage is divided into several 100-g portions. How many portions are there?
Mademuasel [1]

Answer:

20 portions

Step-by-step explanation:

2 kg = 2000 g

2000 / 100 = 20

Hope this helped! :)

7 0
3 years ago
Can y’all help me plz?
gulaghasi [49]

Answer:

13

Step-by-step explanation:

Pythagreom Therom:

a^2+b^2=c^2

12^2+5^2=c^2

144+25=c^2

169=c^2

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3 0
2 years ago
The mean number of hours of part-time work per week for a sample of 526526 college students is 2828. If the margin of error for
sveta [45]

Answer:

The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.

Step-by-step explanation:

A confidence interval has the following format.

\mu_{x} \pm M

In which \mu_{x} is the mean of the sample and M is the margin of error.

In this problem, we have that:

\mu_{x} = 28, M = 2.2

\mu_{x} - M = 28 - 2.2 = 25.8

\mu_{x} + M = 28 + 2.2 = 30.2

The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.

4 0
3 years ago
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