Question

A job candidate at a large job fair can be classified as unacceptable, provisional, or acceptable. Based on past experience, a high-quality candidate is expected to get 80 percent acceptable ratings, 15 percent provisional ratings, and 5 percent unacceptable ratings. A high-quality candidate was evaluated by 100 companies and received 60 acceptable, 25 provisional, and 15 unacceptable ratings. A chi-square goodness-of-fit-test was conducted to investigate whether the evaluation of the candidate is consistent with past experience. What is the value of the chi-square test statistic and number of degrees of freedom for the test

Answer 1

Answer:

chisquare = 31.667

degree of freedom = 2

Step-by-step explanation:

Formula for chisquare test =  (O-E)²/E

total number observations= 60 + 25 + 15 = 100                  

Estimated E,

80% x 100 = 80

15%x100 = 15

5% x 100 = 5

chisquare =

$\frac{(60-80)^{2} }{80} +\frac{(25-15)^{2} }{15}+\frac{(15-5)^{2} }{5}$

= 5 + 6.67 + 20

= 31.667

from the calculation above the value of the chisquare statistic = 31.67

the degree of freedom is the number of samples in the test  n - 1

= 3-1

= 2

I have solve this question also in a tabular form to aid understanding in the file i uploaded.

thank you and good luck!