Given:
In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle.
To find:
The measures of the 2 acute angles of the triangle.
Solution:
Let x be the measure of one acute angle. Then the measure of another acute is (2x+12).
According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees. So,




Divide both sides by 3.


The measure of one acute angle is 26 degrees. So, the measure of another acute angle is:



Therefore, the measures of two acute angles are 26° and 64° respectively.
4x+40-3x-2-x
(4x-3x-x)=4x-4x=0
(40-2)=38
The answer will be 38
The formula for graphing is y=mx+b, where m is the slope and b is the slope-intercept (where the line is at x=0). In this case, the slope is 10. Hope this helps and please give branliest!
B = ym + y
B - y = ym
(B - y) / y = m
or
B/y - 1 = m
Answer: 3 + a + 10b
Step-by-step explanation: combine like terms