What happens when water is heated for long?

Someone fires a 0.04 kg bullet at a block of wood that has a mass of 0.5 kg. (The block of wood is sitting on a frictionless sur

lidiya [134]

Answer:

22.22m/s

Explanation:

The momentum before a collision = momentum after collision so...

work out the momentum of the first object (the bullet)

its p = mv

0.04 kg × 300 m/s = 0.54 kg × v

rearrange this to find v which is 0.04 x 300 = 12

so 12 = 0.54 x v

12/0.5 = v

v = 22.22m/s

hope this helps!

7 0

3 years ago

This is physics 11th grade and a homework question I don’t understand how to do this or what the question is asking me

Alexxx [7]

a) Frequency is the number of complete oscillations per second. Looking at the graph, there are 9 complete oscillations in 5 seconds. Thus,

Frequency = 9/5 = 1.8 oscillations per second

Frequency = 1.8 Hz

Period = 1/frequency = 1/1.8

Period = 0.056 s

b) When we differenctiate displacement with respect to time, the result is velocity.

Recall, period = 1/f = 5/9 cycles

1/4 cycle behind = 1/4 x 5/9 = 5/36

It is delayed with 5/36 sec with respect to displacement.

5/36 sec = 0.139 sec

Acceleration = first derivative of velocity = second derivative of displacement = 1/4 cycle behind velocity = 1/2 cycle behind displacement =

5/36 = 0.139 sec delayed with respect to velocity

= 5/18 = 0.2777 secs delayed with respect to displacement

Thus, the number of seconds out of phase with the displacements is 0.278 seconds

c) The formula for calculating the period of an ideal pendulum anywhere is

T = 2π√length/local gravity). We would calculate the local gravity.

From the information given,

length = 0.2

T = P = 5/9

Thus,

5/9 = 2π√0.2/local gravity)

(5/9)/2π = √0.2/local gravity

Square both sides. It becomes

[(5/9)/2π]^2 = 0.2/local gravity

local gravity = 0.2/[(5/9)/2π]^2

local gravity = 25.56 m/s^2

Thus,

acceleration due to gravity = 25.56 m/s^2

Recall, earth's gravity = 9.8 m/s^2

number of g forces = 25.56/9.8

number of g forces = 2.61

6 0

1 year ago

Two points are located on a rigid wheel that is rotating with decreasing angular velocity about a fixed axis. Point A is located

Norma-Jean [14]

d.Both points have the same instantaneous angular velocity.

Explanation:

Let's analyze each option one by one:

a.the angular velocity at point A is greater than that of point B. --> FALSE. In fact, for a rigid body (such as the rigid wheel in this problem), all the points along the body rotates with the same angular velocity. This is because the angular velocity is defined as

$\omega=\frac{\theta}{t}$

where $\theta$ is the angular displacement and t is the time taken. Therefore, all the points rotate by the same angle $\theta$ in the same time t.

b.Both points have the same centripetal acceleration. --> FALSE. The centripetal acceleration of a point along the disk is given by

$a_c=\omega^2 r$

where $\omega$ is the angular velocity and r is the distance of the point from the axis of rotation. Here A is located farther away from the axis with respect to B, so it will have a greater centripetal acceleration.

c.Both points have the same tangential acceleration. --> FALSE. The tangential acceleration is given by

$a_t = \alpha r$

where $\alpha$ is the angular acceleration. $\alpha$ is the same for every point for a rigid body, but $r$ is not (A is located farther away), so A and B do not have same tangential acceleration.

d.Both points have the same instantaneous angular velocity. --> TRUE. This is true for what we said at point A).

e.Each second, point A turns through a greater angle than point B. --> FALSE. The two points cover the same angular displacement in the same time, since they have same angular velocity.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

4 0

4 years ago

Which of the following are equivalent units?

asambeis [7]

Answer : The correct options are, (B) a newton-meter and a joule and (C) a newton and a joule/sec

Explanation :

As we know that,

$1N=1Kg\text{ m }s^{-2}\\\\1J=1\text{Kg }m^2s^{-2}\\\\1W=1\text{Kg }m^2s^{-3}$

or we can say that,

$1W=1J/s\\\\1J=1Nm\\\\1N=1J/s\\\\1W=1Nms^{-1}$

From the given options, the option B and C are the equivalent units.

Hence, the correct options are, (B) and (C)

3 0

4 years ago

Read 2 more answers

If you could live on the moon through one lunar cycle, how you would experience the phases of the moon?

raketka [301]

Wherever you're sitting on the moon, the sun would be up and shining on you for about two Earth weeks, then the sun would be down and you would be in pitch dark for the next two weeks. You would have no idea of the "phases", because they're only visible to someone on Earth. BUT . . . If you really knew what's what, you could always know what moon phase people on Earth are seeing right now ... but you would need to be somewhere on the side of the moon that always faces Earth. Then, the Earth would always be in your sky, and IT would go through phases for you ! And you would know that the Earth phase you're seeing is exactly the same as the moon phase that people down there are seeing, only BACKWARDS ... the section of the Earth that's DARK for you is the same shape as the section of the moon that's LIGHT for the people down there. Is that cool or what !

5 0

4 years ago

What happens when water is heated for long?​

What happens when water is heated for long?