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mote1985 [20]
3 years ago
8

Consider a car moving with a constant velocity of 90 m/s. What is it’s acceleration.

Physics
2 answers:
Sholpan [36]3 years ago
6 0

Consider a car moving with a constant velocity of 90 m/s. What is it’s acceleration.

<u>Zero</u>

Troyanec [42]3 years ago
5 0

Answer:

Zero

Explanation:

Acceleration is rate of change of velocity..

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A ball having a weight of 1.5 N is dropped from a height of 4 meters. (Neglect air friction.) How much mechanical energy is "los
NikAS [45]
As this mechanical energy is associated with height, it would be "Potential Energy" in particular.

U = mgh
U = F.h
U = 1.5 * 4
U = 6 Joules

So, 6 J of energy is lost before it hits the ground.

Hope this helps!
4 0
3 years ago
Read 2 more answers
What are some modern uses for infrasound example, ultrasound can be used in the medical field to look inside people. Thanks!
lyudmila [28]
Infrasound sound is any sound that are below the sound a human can hear, elephants use it to communicate with other elephants.
5 0
3 years ago
The name (blank) means "all land"
mina [271]
I would say the answer is Pangaea.  I got this answer but google searching "all land" means what...  and the 3rd or 4th one down it says Answers.com
But i worn you answers.com is a very slow sight...
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4 0
3 years ago
Which weather event is capable of destroying homes and uprooting trees due to a low pressure area at its center
Bond [772]

You're talking about a <em>tornado</em>.

It's not so much the low pressure that's so dangerous in the center of a tornado.  It's more a matter of the high winds that are <em>caused </em>by the low pressure.

7 0
3 years ago
Read 2 more answers
Problem 21-40a:
Greeley [361]

Answer:

Part a)

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

q = 3.37 \times 10^{-4} C

Explanation:

As we know that electric force on electric charge is given as

F = qE

here we have

q = 1.6 \times 10^{-19}C

E = 153 N/C

now force is given as

F = (1.6 \times 10^{-19})(153) = 2.45 \times 10^{-17} N

Gravitational force on electric charge near surface of earth is given as

F_g = mg

F_g = (9.1 \times 10^{-31})(9.81) = 8.93 \times 10^[-30} N

now the ratio of two forces is given as

\frac{F_e}{F_g} = \frac{2.45 \times 10^{-17}}{8.93 \times 10^{-30}}

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

Now the ball is balanced by the electric force and the force of gravity on it

so here we have

F_g = qE

mg = qE

(5.25 \times 10^{-3})(9.81) = q(153)

here we have

q = 3.37 \times 10^{-4} C

8 0
3 years ago
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