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ziro4ka [17]
2 years ago
13

1. Give 3 examples of waves that carry small amounts of energy?​

Physics
1 answer:
masya89 [10]2 years ago
4 0

ANSWER:

  1. Radio waves
  2. Micro waves
  3. Infrared waves

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Give a calculate answer to show that the two values (English system and metric system) for the Planck Constant are equivalent.
Nataly_w [17]

Answer:

Given values of Planck Constant are equivalent in English system and metric system.

Explanation:

Value of Planck's constant is given in English system as 4.14 x 10⁻¹⁵eV s.

Converting this in to metric system .

We have 1 eV = 1.6 x 10⁻¹⁹ J

Converting

     4.14 x 10⁻¹⁵eV s = 4.14 x 10⁻¹⁵x 1.6 x 10⁻¹⁹ = 6.63 x 10⁻³⁴ Joule s

So Given values of Planck Constant are equivalent in English system and metric system.

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3 years ago
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Answer:

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5 0
3 years ago
An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. the heavie
Doss [256]
By conservation of momentum,
Distance lighter fragment slide= 7*6.7=46.9m
6 0
2 years ago
To prevent accidental electric shock, most electrical equipment is A. painted. B. isolated. C. coated. D. grounded.
Nesterboy [21]
D. It is Grounded below ground 
4 0
3 years ago
Read 2 more answers
An electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat
Ivahew [28]

Answer:

The electric field is directed toward the electron and has a magnitude of E=\frac{ke}{r^{2} }.

Explanation:

An electric field is define as the surrounding of charges which exert a force on each other and this force can be attractive or repulsive depends on the charge.

In the given case electron is given and the magnitude of charge on electron is e=1.6\times 10^{-19}C

Electric field can be represented as,

E=\frac{kQ}{r^{2} }

Here, r is the distance between the point ande charge, k is the electric field constant and Q is the charge.

In the given question an electron is given so electric field will be,

E=\frac{ke}{r^{2} }

As we know that electric field start from the positive charge and vanish in the negative charge.

So, here the electric field will be E=\frac{ke}{r^{2} } and it is directed toward the electron because of negative charge on the electron.

6 0
2 years ago
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