Answer:
Explanation:
pressure decreases with increasing altitude. The pressure at any level in the atmosphere may be interpreted as the total weight of the air above a unit area at any elevation. At higher elevations, there are fewer air molecules above a given surface than a similar surface at lower levels.
The force of the person is 90 newtons away from the wall.
<h3>What is force?</h3>
Force can be defined as the product of mass and acceleration.
To calculate the force of the person when pushing off the wall, use the formula below.
Formula:
- F = ma................. Equation 1
Where:
- F = Force off the wall
- m = mass of the person
- a = acceleration of the person
From the question,
Given:
- m = 90 kg
- a = 1 m/s² off the wall
Substitute these values into equation 1
- F = 90×1
- F = 90 Newtons away from the wall
Hence, the force of the person is 90 newtons away from the wall.
Learn more about force here: brainly.com/question/12970081
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Answer:
The average emf induced in the loop is 0.25 V
Explanation:
Given;
area of loop, A = 0.20 m²
strength of magnetic field, B = 50 mT
time, t = 40 ms
where;
Φ is magnetic flux, this is maximum when the plane of the loop is parallel to the magnetic field.
Φ = BA
induced emf = BA / t
induced emf = (50 mT x 0.20 m² ) / (40 ms)
induced emf = 0.25 V
Therefore, the average emf induced in the loop is 0.25 V
You will have to google these constants for yourself. I am warned not to give you the references.
Givens
=====
The given constant acceleration of the sun = 273.7 m/s^2
The Radius of the sun = 695,700 km
Radius of the star = 20 km
acceleration on the star's surface = a1
Formula
======
m_test * a_sun = G * m_test * mass_sun /( r_sun)^2
=========== . . .=========================
m_test * a_sun. . . G* m_test* mass_star / (r_star)^2
There is a lot oc cancellation. The result is.
a_sun / a_star = (r_star)^2 / r^2 Now all you have to do is substitute
Calculations
==========
273.7 / a _ star = (20 000)^2 / (695700 )^2
a_star = 273.7 * (695700)^2 / (20000)^2
a_star = 331176 m/s^2 which is pretty big
Answer:
50 J
Explanation:
Work, W=Fd where F is the applied force and d is the distance
Substituting 10 N for F and 5 m for d then work done on the book can be expressed as
W=10 N* 5 m=50 Nm= 50 J
Therefore, the work done is equivalent to 50 J