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timurjin [86]
3 years ago
8

An unknown element is found to have two naturally occurring isotopes, 200X and 210X with atomic masses of 200.028 and 210.039 re

spectively. If the percent abundance of 200X is 40.00%, what is the average atomic mass of X.
Physics
1 answer:
Kruka [31]3 years ago
5 0

Answer:

The average atomic mass of X is 206.0346

Explanation:

Atomic mass of 200X = 200.028

% abundance of 200X = 40% = 40/100 = 0.4

Atomic mass of 210X = 210.039

% abundance of 210X = 100% - 40% = 60% = 60/100 = 0.6

Average atomic mass of X = (0.4×200.028) + (0.6×210.039) = 80.0112 + 126.0234 = 206.0346

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Q=977216.256\ J=977.216\ kJ

Explanation:

Given:

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<em>When we cool the steam of 100°C then firstly it loses its latent heat to convert into water of 100°C and the further cools the water.</em>

<u>Now the heat removed from steam to achieve the final state of water:</u>

\rm Q=latent\ heat\ of\ vapourization+sensible\ heat\ of\ water

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Q=384(2256+4.186\times (100-31))

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