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Vitek1552 [10]
3 years ago
10

Two protons are aimed directly toward each other by a cyclotron accelerator with speeds of 1200 km/s , measured relative to the

earth. Find the maximum electrical force that these protons will exert on each other?
Physics
1 answer:
Radda [10]3 years ago
8 0

Answer:

The maximum electrical force is 2.512\times10^{-2}\ N.

Explanation:

Given that,

Speed of cyclotron = 1200 km/s

Initially the two protons are having kinetic energy given by

\dfrac{1}{2}mv^2=\dfrac{1}{2}mv^2

When they come to the closest distance the total kinetic energy is converts into potential energy given by

Using conservation of energy

mv^2=\dfrac{kq^2}{r}

r=\dfrac{kq^2}{mv^2}

Put the value into the formula

r=\dfrac{8.99\times10^{9}\times(1.6\times10^{-19})^2}{1.67\times10^{-27}\times(1200\times10^{3})^2}

r=9.57\times10^{-14}\ m

We need to calculate the maximum electrical force

Using formula of force

F=\dfrac{kq^2}{r^2}

F=\dfrac{8.99\times10^{9}\times(1.6\times10^{-19})^2}{(9.57\times10^{-14})^2}

F=2.512\times10^{-2}\ N

Hence, The maximum electrical force is 2.512\times10^{-2}\ N.

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An influence upon an oscillatory system that has the effect of reducing/restriction or preventing its oscillations. Damping is produced by processes that dissipate the energy stored in the oscillation.
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A spring attached to the ceiling is stretched 2.45 meters by a four kilogram mass. If the mass is set in motion in a medium that
denpristay [2]

Answer:

d²x/dt² = - 4dx/dt - 4x is the required differential equation.

Explanation:

Since the spring force F = kx where k is the spring constant and x its extension = 2.45 equals the weight of the 4 kg mass,

F = mg

kx = mg

k = mg/x

= 4 kg × 9.8 m/s²/2.45 m

= 39.2 kgm/s²/2.45 m

= 16 N/m

Now the drag force f = 16v where v is the velocity of the mass.

We now write an equation of motion for the forces on the mass. So,

F + f = ma (since both the drag force and spring force are in the same direction)where a = the acceleration of the mass

-kx - 16v = 4a

-16x - 16v = 4a

16x + 16v = -4a

4x + 4v = -a where v = dx/dt and a = d²x/dt²

4x + 4dx/dt = -d²x/dt²

d²x/dt² = - 4dx/dt - 4x which is the required differential equation

6 0
3 years ago
A 3" diameter germanium wafer that is 0.020" thick at 300K has 1.015 x 10^17 As atoms added to it. What is the resistivity of th
Ber [7]

Answer:

0.546 ohm / μm

Explanation:

Given that :

N = 1.015 * 10^17

Electron mobility, u = 3900

Hole mobility, h = 1900

Ng = 4.42 x10^22

q = 1.6*10^-19

Resistivity = 1/qNu

Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)

= 0.01578880889 ohm /cm

Resistivity of germanium :

R = 1 / 2q * sqrt(Ng) * sqrt(u*h)

R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)

R = 1 /0.0001831

R = 5461.4964 ohm /cm

5461.4964 / 10000

0.546 ohm / μm

7 0
3 years ago
A demented scientist creates a new temperature scale, the "Z scale." He decides to call the boiling point of nitrogen 0°Z and th
slavikrds [6]

Answer:

A) Z = 0.577 C +112.931

Z = 0.577*(100) +112.931=170.631 Z

B) C=\frac{Z-112.931}{0.577}= \frac{100-112.931}{0.577}=-22.41 C

C) K = C +273.15

K = -22.41 +273.15 =250.739 K

Explanation:

For this case we want to create a function like this:

Z = a C + b

Where Z represent the degrees for the Z scale C the Celsius grades and  tha valus a and b parameters for the model.

The boiling point of nitrogen is -195,8 °C

The melting point of iron is 1538 °C

We know the following equivalences:

-195.8 °C = 0 °Z

1538 °C = 1000 °Z

Let's say that one point its (1538C, 1000 Z) and other one is (-195.8 C, 0Z)

So then we can calculate the slope for the linear model like this:

a = \frac{z_2 -z_1}{c_2 -c_1}= \frac{1000 Z- 0Z}{1538C -(-195.8 C)}=\frac{1000 Z}{1733.8 C}=0.577 \frac{Z}{C}

And now for the slope we can use one point let's use for example (-195.8C, 0Z), and we have this:

0 = 0.577 (-195.8) + b

And if we solve for b we got:

b = 0.577*195.8 =112.931 Z

So then our lineal model would be:

Z = 0.577 C +112.931

Part A

The boiling point of water is 100C so we just need to replace in the model and see what we got:

Z = 0.577*(100) +112.931=170.631 Z

Part B

For this case we have Z =100 and we want to solve for C, so we can do this:

Z-112.931 = 0.577 C

C=\frac{Z-112.931}{0.577}= \frac{100-112.931}{0.577}=-22.41 C

Part C

For this case we know that K = C +273.15

And we can use the result from part B to solve for K like this:

K = -22.41 +273.15 =250.739 K

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9- Under what circumstances would a vector have components that are equal in
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Explanation:

c. if the vector is oriented at 0° from the X -axis.

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