The test statistic z will be equal to -0.946 and it shows that there is no significant difference in the proportion of rehires between full time and part time.
Given sample sizes of 833 and 386 and result of samples 434 and 189.

Proportion  of full time=434/833=0.52
Proportion of part time=189/386=0.49.
Difference in proportion =0.52-0.49
 TTF- i∈ rho=0
TTF- i∈ rho=0
 TTF+i∈ rho≠0.
 TTF+i∈ rho≠0.
Mean of difference=0.03
Z=(X-μ)/σ
σ=
=0.0317
σ=0.0317
z=(0-0.03)/0.0317
=-0.03/0.0317
=-0.317
p value will be =0.1736.
Because p value is greater than 0.01 so we will accept the null hypothesis which shows that there is no significant difference in the proportions.
Hence there is no significant difference in the proportion of rehires between full time and part time.
Learn more about z test at brainly.com/question/14453510
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Answer:
585 is the answer of your question.
Step-by-step explanation:
 because formula is 
Mp _ d% of mp
 
        
                    
             
        
        
        
The solution for this problem would be:
f'(x) = 1 - 1/x^2 = (x^2 - 1)/x^2 
is positive where |x| > 1 
hence (-inf, -1) and (1, inf) are the regions in which f' is positive and therefore f is increasing.
Therefore, the answer is (-infinity,-1] U [1,infinity).
        
             
        
        
        
If there is 1000 seats, and the students took 45% percent of them, then 450 sixth graders went on the trip